Answer:
ΔCFE is a right triangle
ΔBEC is an acute triangle
ΔBFG is an equilateral triangle
ΔGAF is an obtuse isosceles triangle
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
RS is 68 and T is 92 if you want an explanation then i gotten but u said quick so maybe it is timed idk
MP = 15 -3 = 12
h/MP = 3/h
h / 12 = 3/h
h^2 = 36
h = 6
