Divide 5x^2 +6x-9 into 25x^4+19x^2-x-78

Simplify the expression 4p−5(p+6) Please help, thank you :)

ankoles [38]

Answer:

-p - 30

Step-by-step explanation:

Hope this helps

3 0

3 years ago

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A and b are natural numbers. The diameter of cell a is 2.3 , and the diameter of cell b is 2.3 .

Pani-rosa [81]

After clarification we see the respective diameters are

$A = 2.3 \times 10^{-a}$

$B = 2.3 \times 10^{-b}$

We're asked about the ratio

$A:B = 2.3 \times 10^{-a} : 2.3 \times 10^{-b} = 10^{-a} : 10^{-b} = 10^b : 10^a = 10^{b-a} : 1$

Now we can go through the choices.

A. If a = 4 and b = 6, then cell a is 100 times greater than cell b.

$A:B=10^{6-4}:1 = 100:1$

It would be more proper to say the diameter of cell A is 100 times the diameter of cell B, but yes, this is TRUE.

B. If a = 4 and b = 6, then cell b is 100 times greater than cell a.

FALSE. 10 to the minus 4 is 100 times bigger than 10 to the minus 6, so a is bigger.

C. If a = 4 and b = 6, then cell a is 2 times greater than cell b.

FALSE. We already calculated its 100 times bigger.

D. If a = 4 and b = 6, then cell b is 2 times greater than cell a.

FALSE.

8 0

4 years ago

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Sue and Cathy have $20 left for a cab fare home.the cab fare is $3 per mile plus a $2 fixed charge.what is the maximum number of

PIT_PIT [208]

Answer:

They would by able to go 4 miles.

Step-by-step explanation:

7 0

3 years ago

How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w

sergejj [24]

The sound wave with a frequency of 20 waves/sec is 800 longer than the wavelength of a sound wave with a frequency of 16,000 waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a frequency of 20 waves/sec is 800 longer than the wavelength of a sound wave with a frequency of 16,000 waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0

2 years ago

Your neighbor has a bag with 5 oranges and 7 apples in it. You will be receiving two pieces of fruit from your neighbor. What is

Snezhnost [94]

Answer:

31.82% probability that you will receive 2 apples.

Step-by-step explanation:

The fruits are removed from the bag, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

5 + 7 = 12 total fruits, which means that $N = 12$

7 apples, which means that $k = 7$

You receive 2 fruits, which means that $n = 2$

What is the probability, in percent, that you will receive 2 apples, assuming she removes them from the bag in random order?

This is, as a proportion, P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,12,2,7) = \frac{C_{7,2}*C_{5,0}}{C_{12,2}} = 0.3182$

0.3182*100% = 31.82%

31.82% probability that you will receive 2 apples.

4 0

3 years ago