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3 years ago

If f(x)= x^2+x and h(x)=5x-2 find f(f(2))

Mathematics

1 answer:

alexandr1967 [171]3 years ago

7 0

<h3>Answer: 2f^2 </h3>

Step-by-step explanation:

Remove the parentheses: = ff x 2

Apply exponent rule: f^1+^1x2

Add the numbers 1+1=2 = 2f^2

I hope this is right.

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HELP ASP

kenny6666 [7]

Answer:

The answer js 203 inches and this is the answer because the teacher said it js correct and it will be the correct one

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2 years ago

Find the indicated values, where g(t)=t^2-t and f(x)=1+x g(f(2)+3)

sleet_krkn [62]

Answer:

$g(f(2)+3)=30$

Step-by-step explanation:

We have the two functions:

$g(t)=t^2-t\text{ and } f(x)=1+x$

And we wish to find:

$g(f(2)+3)$

First, let’s find f(2) first. So, we will substitute 2 for x for f(x):

$f(2)=1+(2)=3$

Hence, we can now substitute 3 for f(2):

$g(f(2)+3)=g(3+3)=g(6)$

Now, we can find g(6). Substitute 6 for t for g(t):

$g(6)=(6)^2-(6)=36-6=30$

Therefore:

$g(f(2)+3)=30$

4 0

3 years ago

Graph the system of linear inequalities.<br> y > 3x + 2<br> y ≤ 3x − 4

Alisiya [41]

$y > 3 \times 2 \\ solve \: for \: y \\ y > 6 \\ ye \: {6 + \infty }$

Sorry that's all i know

<h3>that is in my answer</h3>

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8 0

3 years ago

Write an equation of a like that passes through the points (9,5) and (6,7)

hodyreva [135]

Answer:

y=-2/3x+11

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-5)/(6-9)

m=2/-3

m=-2/3

y-y1=m(x-x1)

y-5=-2/3(x-9)

y=-2/3x+18/3+5

y=-2/3x+6+5

y=-2/3x+11

5 0

3 years ago

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Feliz [49]

9514 1404 393

Answer:

x = 21

Step-by-step explanation:

The parallel lines divide the segments proportionally.

x/27 = 28/36

x = 27(28/36) . . . . multiply by 27 (in your head: (3·9)(4·7)/(4·9) = 3·7)

x = 21

8 0

3 years ago