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jek_recluse [69]
3 years ago
13

A windmill converts the mechanical energy of wind into ?

Physics
1 answer:
sammy [17]3 years ago
7 0
Electric power most likely. It can be a generator for a power plant if needed. Hope this helped. Sorry if it didn't.
You might be interested in
what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?​
Ghella [55]

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

P₂ = Power of second lens = - 2D

Therefore,

P = - 5D - 2D

P = - 7D

Now, the focal length can be given as:

f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\

<u>f = - 0.143 m = - 14.3 cm</u>

Negative focal length indicates that combination will act as diverging lens.

6 0
3 years ago
2. Using the same list of living things show how they could be classified into three groups.
kati45 [8]
You can do animals that have 4 legs (dogs, horses), animals that fly (parrot, eagle), animals that live in the water (goldfish,bass)
3 0
3 years ago
Read 2 more answers
A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center
blagie [28]

Explanation:

Given that,

Mass of the particle, m = 4 kg

Speed of the particle, v = 2.5 m/s

The radius of the circle, r = 2 m

We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :

L=mvr

Substitute all the values,

L=4\times 2.5\times 2\\\\L=20\ kg{\cdot}m^2s

So, the angular momentum of the particle is 20 kg-m² s.

6 0
3 years ago
Part C
7nadin3 [17]

Answer:

yu counter the arguement by either walking out or confronting whats the problem then fixing that problem

5 0
3 years ago
A race car starts from rest on a circular track of radius 378 m. The car's speed increases at the constant rate of 0.580 m/s2. A
insens350 [35]

Answer:

a) V=14.904m/s

b) d = 191.49 m

c) t= 25.696 s

Explanation:

From the question we are told that:

Radius r =378m

Acceleration a=0.580

a)

Generally the  equation for speed of the car is mathematically given by

 a=\frac{v^2}{r}

 V=\sqrt{a*r}

 V=\sqrt{0.58*383}

 V=14.904m/s

b)

Generally the  equation for distance traveled of the car is mathematically given by

 V^2=u^2+2ad

 d=\frac{V^2}{2a}

 d=\frac{14.904^2}{2*0.58}  

 d = 191.49 m

c)

Generally the  equation for time of the car is mathematically given by

 V=u+at

 t=\frac{V}{a}

 t=\frac{14.904}{0.58}

 t= 25.696 s

3 0
3 years ago
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