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Angelina_Jolie [31]
3 years ago
7

Consider the waves on a vibrating guitar string and the sound waves the guitar produces in the surrounding air. The string waves

and the sound waves must have the same velocity. wavelength. frequency. amplitude. More than one of the above is true.
Physics
1 answer:
tatiyna3 years ago
5 0

Answer:

Frequency is the correct answer.

Explanation:

When a wave go from one medium to another medium then the velocity, wavelength and Amplitude changes. But there is no change on the frequency.

Here, The string and the surroundings air are two medium , from which the wave travels.

So, the wave has same frequency in both medium.

The correct answer is Frequency.

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How much tension must a rope withstand if it is used to accelerate 70.0 skier behind a boat at 1.50m/s^2?
SIZIF [17.4K]
It will  be stand 46.67 all i did was divide both numbers but im not sure if im right but i hope i am hope i helped:)
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Wrapping paper is being unwrapped from a 5.0-cm radius tube, free to rotate on its axis. if it is pulled at the constant rate of
lisov135 [29]
So the equation for angular velocity is

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In order to find T, the tangential velocity is

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When calculated, I got V = 3.14

When you enter that into the angular velocity equation, you should get 2m/s
5 0
3 years ago
Convert 70 mi/h to m/s. 1 mi = 1609 m.<br><br> Answer in units of m/s.<br><br> Plz help me now
melisa1 [442]

Answer:

70mi/h

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6 0
3 years ago
For this problem, we assume that we are on planet-i. the radius of this planet is r =4200 km, the gravitational acceleration at
Minchanka [31]
The expression commonly used for potential gravitational energy is just simplification. It is actually just the first term in Taylor expansion of the real expression. 
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U=-G \frac{mM}{r}
Where G is universal gravitational constant, and r is the distance between the objects centers of mass. Negative sign represents the bound state.
Since we are not given the mass of the planet we have to calculate it.
F_g=G\frac{mM}{r_p^2}\\ mg=G\frac{mM}{r_p^2}\\ g=G\frac{M}{r_p^2}
This formula can be used for any planet. It gives you the gravitational acceleration on the planet's surface. We can use it to calculate the planet's mass:
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Now we can calculate the potential energy of that cannonball when it reaches its maximum height.
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E_k=4.99\cdot 10^{10} J

3 0
3 years ago
4. With respect to a mass of 1kg. (a) How much change in elevation must it undergo to change its potential energy by 1 kJ? (g=9.
mojhsa [17]

Answer:

102 m upwards.

Explanation:

Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.

Fixed that work being 1 kJ, we get

\vec F \cdot \vec{ \Delta h} = |F| |\Delta h| cos 0 = ( 9.8 N )\Delta h \cdot 1 = 10^3 J\\\Delta h = \frac {10^3}{9,8} m \approx 102 m

4 0
1 year ago
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