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Vika [28.1K]
3 years ago
6

In the following diagram, the voltage is 1.5 volts and the resistance is 0.35 ohms. Use Ohm's Law to determine the current in th

e circuit.
0.53 amps
4.3 amps
0.23 amps
1.5 amps

Physics
1 answer:
natulia [17]3 years ago
3 0

Current = (voltage) / (resistance)

= (1.5 V) / (0.35 ohms)

= 4.28 Amperes.

==> The battery will not last long.

==> The ammeter is broken ... it's reading less than 0.25 Amps.
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Does the galvanometer deflect to the left or the right when:________
igomit [66]

Complete question is;

Does the galvanometer deflect to the left or the right when

a) the magnet is being pushed in

b) the magnet is being pulled out

c) the magnet is being held steady?

Answer:

Option A - when the magnet is being pulled out

Explanation:

Faraday’s law of electromagnetic induction states that: “Voltage is induced in a circuit whenever relative motion exists between the conductor and the magnetic field, and the magnitude of the voltage will be proportional to the rate of change of the flux”.

Now, applying it to the question, When the magnet is moved towards the sensitive center of the galvanometer and then pulled out, the needle of the galvanometer will deflect away from its center position in one direction only but when it is held steady, the needle of the galvanometer will return back to zero.

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3 years ago
A hawk is flying horizontally at 18.0 m/s in a straight line, 230 m above the ground. A mouse it has been carrying struggles fre
Lisa [10]

Answer:

a) vd = 47.88 m/s

b) θ = 80.9°

c) t = 6.8 s

Explanation:

In the situation of the problem, you can assume that the trajectory of the hawk and the trajectory of the mouse form a rectangle triangle.

One side of the triangle is the horizontal trajectory of the hawk after 2.00s of flight, the other side of the triangle is the distance traveled by the mouse when it is falling down. And the hypotenuse is the trajectory of the hawk when it is trying to recover the mouse.

(a) In order to calculate the diving speed of the hawk, you first calculate the hypotenuse of the triangle.

One side of the triangle is c1 = (18.0m/s)(2.0s) = 36m

The other side of the triangle is c2 = 230m - 3m = 227 m

Then, the hypotenuse is:

h=\sqrt{(36m)^2+(227m)^2}=229.83m    (1)

Next, it is necessary to calculate the falling down time of the mouse, this can be done by using the following formula:

y=y_o+v_ot+\frac{1}{2}gt^2    (2)

yo: initial height = 230m

vo: initial vertical speed of the mouse = 0m/s

g: gravitational acceleration = -9.8m/s^2

y: final height of the mouse = 3 m

You replace the values of the parameters in (2) and solve for t:

3=230-4.9t^2\\\\t=\sqrt{\frac{227}{4.9}}=6.8s

The hawk traveled during 2.00 second in the horizontal trajectory, hence, the hawk needed 6.8s - 2.0s = 4.8 s to travel the distance equivalent to the hypotenuse to catch the mouse.

You use the value of h and 4.8s to find the diving speed of the hawk:

v_d=\frac{229.83m}{4.8s}=47.88\frac{m}{s}

The diving speed of the Hawk is 47.88m/s

(b) The angle is given by:

\theta=cos^{-1}(\frac{c_1}{h})=cos^{-1}(\frac{36m}{229.83m})=80.9 \°

Then angle between the horizontal and the trajectory of the Hawk when it is descending is 80.9°

(c) The mouse is falling down during 6.8 s

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3 years ago
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Elan Coil [88]

Answer:D

Explanation:

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1 year ago
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