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Temka [501]
3 years ago
15

Can someone please help me

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0
You gotta post a picture of the graph
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Factor the expression completely.<br> 625x4 - 256y4
scoundrel [369]

<u>Answer:</u>

<u>(625 • (x4)) -  28y4</u>

<u></u>

<u>  54x4 -  28y4 3.1      Factoring:  625x4-256y4  </u>

<u> </u>

<u>Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B) </u>

<u> </u>

<u>Proof :  (A+B) • (A-B) = </u>

<u>         A2 - AB + BA - B2 = </u>

<u>         A2 - AB + AB - B2 = </u>

<u>         A2 - B2Note :  AB = BA is the commutative property of multiplication. </u>

<u> </u>

<u>Note :  - AB + AB equals zero and is therefore eliminated from the expression. </u>

<u> </u>

<u>Check :  625  is the square of  25  </u>

<u>Check : 256 is the square of 16 </u>

<u>Check :  x4  is the square of  x2  </u>

<u> </u>

<u>Check :  y4  is the square of  y2  </u>

<u> </u>

<u>Factorization is :       (25x2 + 16y2)  •  (25x2 - 16y2)  3.2      Factoring:  25x2 - 16y2  </u>

<u> </u>

<u>Check :  25  is the square of  5  </u>

<u>Check : 16 is the square of 4 </u>

<u>Check :  x2  is the square of  x1  </u>

<u> </u>

<u>Check :  y2  is the square of  y1  </u>

<u> </u>

<u>Factorization is :       (5x + 4y)  •  (5x - 4y)this is the answer: (25x2 + 16y2) •(5x + 4y) • (5x - 4y)</u>

5 0
3 years ago
John has a circular pool that has a radius of 7 feet. What is the area of his pool? Please use the formula sheet to assist you w
andrew-mc [135]

Answer:

153.86 square feet

Step-by-step explanation:

The formula for the area of a circle is A=πr2

area = pi x radius squared

the radius is 7 feet, square that to get 49

multiply 49 by pi to get the area: 153.86 square feet

5 0
3 years ago
Read 2 more answers
In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

  • \angle DIH\cong \angle EGH as alternate interior angles;
  • \angle DHI\cong \angle GHE as vertical angles;
  • DH\cong HE because point H bisects segment DE (given).

Thus,

\triangle DIH\cong \triangle EGH by AAS postulate

4 0
3 years ago
A. ASA Postulate <br> B. HL Theorem <br> C.AAS Theorem<br> D. SAS Postulate
TiliK225 [7]

Answer:

your answer will be <em><u>B. HL Theorem </u></em>

Step-by-step explanation:

hope it helps you...

4 0
3 years ago
Express the area of the entire rectangle.
Alexxandr [17]
2X+9
Combine like terms
4 0
3 years ago
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