Answer:
Transition Element
Explanation:
Transition elements are defined as those elements which can form at least one stable ion and has partially filled d-orbitals. They are also characterized by forming complex compounds and having different oxidation states for a single metal element.
Transition metals are present between the metals and the non metals in the periodic table occupying groups from 3 to 12. There general electronic configuration is as follow,
(n-1)d
¹⁻¹⁰ns
¹⁻²
The general configuration shows that for a given metal, the d sublevel will be in lower energy level as compared to corresponding s sublevel. For example,
Scandium is present in fourth period hence, its s sublevel is present in 4rth energy level so its d sublevel will be present in 3rd energy level respectively.
Hence, we can conclude that for transition metals the electron are present in highest occupied s sublevel and a nearby d sublevel
.
If we work it out with direct proportions, the vapor pressure of propanone is 56 degrees Celsius. The atmospheric pressure is about 101 kPa. If the vapor pressure is equal to the atmospheric pressure, the substance boils. Therefore, if we hold a linear proportion, 45/56 = x/101. 56x = 101*45, x = 101*45/56 = 81. The closest choice here is (3) 70 kPa.
Next time, please provide us with Reference Table H.
Answer:
γ > β > α
Explanation:
The penetrating power is inversely related to the mass. The higher the mass, the lower the penetrating power.
α rays are Helium nucleus (He²⁺), that is, they are formed by 2 protons and 2 neutrons. The mass of an α particle is 4.001 amu.
β rays are nuclear electrons, which result from the decay of a neutron. The mass of a β particle is 1/1840 amu.
γ rays contain no particles and have no mass.
The order of penetrating power is γ > β > α.
Answer:
0.737 L
Explanation:
Charles law states for a fixed amount of gas, volume of the gas is directly proportional to the absolute temperature of the gas at constant pressure
we can use the following equation
V1/T1 = V2/T2
where V1 is volume and T1 is temperature at first instance
V2 is volume and T2 is temperature at the second instance
substituting the values
3.50 L / 727.0 K = V2 / 153.0 K
V2 = 0.737 L
new volume at 153.0 K is 0.737 L
There's less space, causing the air particles to collide with the walls of the container more frequently. Pressure is that energy caused by molecules striking a surface. Thus, compacting air molecules leads to higher pressure.
