Answer:
<h2>3.36J</h2>
Explanation:
Step one:
given data
mass m= 1.3kg
distance moved s= 2.8m
opposing frictional force= 0.34N
assume g= 9.81m/s^2
we know that work done= force *distance moved
1. work done to push the book= 1.55*2.8=4.34J
2. Work against friction = force of friction x distance
= 0.34*2.8=0.952J
Step two:
the work done on the book is the net work, which is
Network done= work done to push the book- Work against friction
Network done= 4.32-0.952=3.36J
<u>Therefore the work of the 1.55N 3.36J</u>
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Answer:
<u>velocity of swimmer relative to ground = 3 i -5 j</u>
Explanation:
- To cross a river the swimmer swims relative to river in perpendicular direction.
Velocity of river = -5 j (south)
Velocity of swimmer relative to river = 3 i(north)
So
<h2>
Velocity of swimmer relative to ground = Velocity of swimmer relative to river + Velocity of river</h2>
Velocity of swimmer relative to ground = 3 i -5 j
So magnitude of total velocity is = =
To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and the geometric relationships that allow us to find the volume of the figures presented.
For the particular case of the Cube with equal sides its volume is determined by
In the case of perforated material we have that its volume is given according to the cylindrical geometry, that is to say
In this way the net volume would be
We need to find the mass, but we have the Weight and Gravity so from Newton's second Law
PART A) From the relation of density as a unit of mass and volume we have to
PART B) To find the weight of the cube then we apply the ratio of