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White raven [17]
1 year ago
10

You redo the primitive yo yo experiment (Figure 1), but instead of holding the free end of the string stationary, you move your

hand vertically so that the tension in the string equals 2M /3. What is the vertical acceleration of the yo yo's cena of mass? Does it accelerate upward or downward? Express your answer to three significant figures and include the appropriate units. Enter positive value of the acceleration is directed upward and negative value if the acceleration is directed downward.
Physics
1 answer:
zhannawk [14.2K]1 year ago
5 0

The vertical acceleration of the yo yo cent  of mass is 0.66 m/s².

We know that, T = M*a

And T is given as 2M/3

2M/3 = M*a

So, a = 0.66 m/s²

What is Acceleration ?

Acceleration is the general term for any process where the velocity changes. There are only two ways to accelerate either by increasing the speed or decreasing direction, or both. The reason for this is that velocity includes both a speed and a direction.

You cannot possibly be accelerating if you don't also change you direction and speed, regardless of how swiftly you are travelling. Due to this, a jet experiences no acceleration even when it is moving at a high speed. In this case, 800 miles per hour, because its velocity is constant.

When it lands, the jet will accelerate as it slows down and quickly come to a stop.

Learn more about Acceleration from given link

brainly.com/question/605631

#SPJ4

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Write short notes on:<br>human made wetland​
kogti [31]

Any type of wetland that has been developed or maintained by humans for uses such as aquaculture, irrigation, or water storage.

<h3>What is a human-made wetland​ ?</h3>

Any kind of wetland that has been created or kept up by people for purposes like water storage, irrigation, or aquaculture.

In India's Punjab state, in the Kapurthala district, lies the man-made Kanji Wetland, which includes the Kanji Lake.

In order to give irrigation facilities to the hinterland, it was built by building the headworks over the perennial Bien River, a tributary of the Beas River.

The Sunderbans are India's biggest wetland. The world's biggest mangrove forest includes Sunderban Wetland.

Hence, the human-made wetland​ is an artificial wetland.

To learn more about the human-made wetland​ refer;

brainly.com/question/1334452

#SPJ1

4 0
3 years ago
Question 1 of 10
natali 33 [55]

Answer: B. A model of a cell is easier to manipulate

Explanation: just took the test//APEX

5 0
3 years ago
A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with
gulaghasi [49]

Answer:

8.8 cm

31.422 cm/s

Explanation:

m = Mass of block = 0.6 kg

k = Spring constant = 15 N/m

x = Compression of spring

v = Velocity of block

A = Amplitude

As the energy of the system is conserved we have

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm

Amplitude of the oscillations is 8.8 cm

At x = 0.7 A

Again, as the energy of the system is conserved we have

\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s

The block's speed is 31.422 cm/s

4 0
3 years ago
The James Webb Space Telescope is positioned around 1.5 million kilometres from the Earth on the side facing away from the Sun.
Bad White [126]

The angular velocity depends on the length of the orbit and the orbital

speed of the telescope.

Response:

First question:

  • The angular velocity of the telescope is approximately <u>0.199 rad/s</u>

Second question:

  • The telescope should accelerates away by approximately F = <u>0.0005·m </u>

Third question:

  • <u>The pulling force between the Earth and the satellite</u>

<h3>What equations can be used to calculate the velocity and forces acting on the telescope?</h3>

The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun

The orbital velocity of the telescope = The Earth's orbital velocity

First question:

Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}

The orbital velocity of the Earth = 29.8 km/s

The distance between the Earth and the Sun = 148.27 million km

The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77

Radius of the orbit, r = 149.77 million kilometer from the Sun

The length of the orbit of the James Webb telescope = 2 × π × r

Which gives;

r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers

Therefore;

Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199

  • The angular velocity of the telescope, ω ≈ <u>0.199 rad/s</u>

Second question:

Centrifugal force force, F_{\omega} = m·ω²·r

Which gives;

F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m

Gravitational \ force,  F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}

Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Mass of the Sun = 1.989 × 10³⁰ kg

Which gives;

F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx   0.00592 \cdot m

Which gives;

F_{\omega} < F_G, therefore, the James Webb telescope has to accelerate away from the Sun

F = \mathbf{F_{\omega}} - \mathbf{F_G}

The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ <u>0.0005·m (away from the Sun)</u>

Third part:

Other forces include;

  • <u>The force of attraction between the Earth and the telescope </u>which can contribute to the the telescope having a stable orbit at the given speed.

Learn more about orbital motion here:

brainly.com/question/11069817

3 0
3 years ago
intial velocity is 45km/h, final velocity is 0, time taken is 3 seconds,calculate the retradation of the vehicle and distance tr
V125BC [204]

Answer:

v= u+at

0=45×1000×60×60+3a

_3a=16200045

a=5400015m per sec

4 0
3 years ago
Read 2 more answers
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