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White raven [17]
1 year ago
10

You redo the primitive yo yo experiment (Figure 1), but instead of holding the free end of the string stationary, you move your

hand vertically so that the tension in the string equals 2M /3. What is the vertical acceleration of the yo yo's cena of mass? Does it accelerate upward or downward? Express your answer to three significant figures and include the appropriate units. Enter positive value of the acceleration is directed upward and negative value if the acceleration is directed downward.
Physics
1 answer:
zhannawk [14.2K]1 year ago
5 0

The vertical acceleration of the yo yo cent  of mass is 0.66 m/s².

We know that, T = M*a

And T is given as 2M/3

2M/3 = M*a

So, a = 0.66 m/s²

What is Acceleration ?

Acceleration is the general term for any process where the velocity changes. There are only two ways to accelerate either by increasing the speed or decreasing direction, or both. The reason for this is that velocity includes both a speed and a direction.

You cannot possibly be accelerating if you don't also change you direction and speed, regardless of how swiftly you are travelling. Due to this, a jet experiences no acceleration even when it is moving at a high speed. In this case, 800 miles per hour, because its velocity is constant.

When it lands, the jet will accelerate as it slows down and quickly come to a stop.

Learn more about Acceleration from given link

brainly.com/question/605631

#SPJ4

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- A fridge has a maximum static friction force
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They will move the fridge if they all push in the same direction, but it will not move with constant velocity

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A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


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