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dezoksy [38]
3 years ago
8

What is the net electrical charge on a magnesium ion that is formed when a neutral magnesium atom loses two electrons?

Physics
2 answers:
Snezhnost [94]3 years ago
6 0

As we know that fundamental charge due to an electron is given by

e = -1.6 \times 10^{-19} C

so here we will say that charge on an atom due to loss of electron is termed as positive charge while due to gain of electron it is negative charge

Here when magnesium loses two electrons it will become positively charged

And total charge on it is given as

Q = Ne

now we know that

N = 2 electrons

so charge on it is given as

Q = 2(1.6 \times 10^{-19}C)

Q = 3.2 \times 10^{-19} C

Arisa [49]3 years ago
4 0
-3.2x10^-19C is formed 
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A car travelling at 20 m/s due north along the highway makes a right turn on to a side road that heads due east. It takes 50 s f
Marrrta [24]

Answer:  initial velocity: 20 m/s

                time taken to complete the turn: 50s

               final velocity: 15 m/s

average acceleration= final velocity-initial velocity/time taken - 0s( 0 is taken here as there was no initial time)

           = 15-20/50-0

           = -5/50= -0.1 ms^2

3 0
3 years ago
A solid ball of radius rb has a uniform charge density rho.
Oksana_A [137]

Note: question B is incomplete.

Complete Question

A solid ball of radius rb has a uniform charge density ρ.

a.  What is the magnitude of the electric field E(r) at a distance r>rb from the center of the ball?  Express your answer in terms of ρ, rb, r, and ϵ0.

b.   What is the magnitude of the electric field E(r) at a distance r<rb from the center of the ball?  Express your answer in terms of ρ, r, rb, and ϵ0.

c.   Let E(r) represent the electric field due to the charged ball throughout all of space. Which of the following statements about the electric field are true?

1. E(0) = 0.

2. E(rb) = 0

3. lim E(r) = 0.

4. The maximum electric field occurs when r = 0.

5. The maximum electric field occurs when r = rb.

6. The maximum electric field occurs as r to infinity.

Answer:

a) the magnitude of E(r)= ρr³/3 ε₀r²

b) the magnitude at distance r from the centre E(r)= ρr/3 ε ₀ ( if r<rb)

c) statements 1(E(0) = 0), 3(E(0) = 0) and 5(The maximum electric field occurs when r = rb.) are true

Explanation:

given

charge density = ρ ,  ε

Volume of sphere , V = (⁴/₃)πr³

a) charge density = charge/volume

ρ = q ÷ V

make charge the subject of the formula

∴q = ρ × V=  ρ× (⁴/₃)πr³

where r³ = rb³(at distance rb³)

recall

E= q/4πε₀r²

E=  ρ × (⁴/₃)πrb³/4πε₀r²

∴E(r)= ρrb³/3 ε ₀r²

(b)  The Gaussian surface is inside the ball, therefore, surface only encloses a portion of ball's charge .

The net charge enclosed by the Gaussian surface is different to the of net charge enclosed in (a)

Recall

E= q/4πε₀r²

V= (⁴/₃)πr³

E=  ρ × (⁴/₃)πr³/4πε₀r²

∴E(r)= ρr/3 ε₀

(c)  E(0)= 0

limr-----∝

E(r)= 0

The maximum electric field occurs when r=rb.

4 0
3 years ago
a charged partocle produces an electric field with a magnitude of 2.0 N/C at a point that is 50cm away from the particle
zheka24 [161]

The charge on the particle is 5.6 × 10⁻¹¹ C.

<h3>Calculation:</h3>

The magnitude of an electric field produced by a charge is given by:

                                                 E = q/ 4πε₀r²

where,

E = electric field

q = charge

r = distance

1/4πε₀ = 8.99 × 10⁹ Nm²/C²

Given,

E = 2.0 N/C

r = 50 cm = 0.5 m

To find,

q =?

Put the values in the above equation:

E = q/ 4πε₀r²

q = E (4πε₀r²)

q = 2.0 × (0.50²)/ 8.99 × 10⁹

q = 5.6 × 10⁻¹¹ C

Therefore, the particle has a charge of 5.6 × 10⁻¹¹ C.

<h3>What is an electric field?</h3>

The physical field that surrounds each electric charge and acts to either attract or repel all other charges in the field is known as an electric field. Electric charges or magnetic fields with different amplitudes are the sources of electric fields.

I understand the question you are looking for is this:

A charged particle produces an electric field with a magnitude of 2.0 N/C at a point that is 50 cm away from the particle. What is the magnitude of the particle's charge?

Learn more about electric field here:

brainly.com/question/14857134

#SPJ4

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"What is the overall length limitation of a UTP cable run from the telecommunications closet to a networking device in the work
Goryan [66]

Answer:

90-100meters

Explanation:

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3 years ago
Once an object enters orbit, what keeps the object moving sideways?
zubka84 [21]

Answer: Inertia!!

Explanation: I just completed the edg quiz and got that answer correct! Hope its not too late for you!

7 0
3 years ago
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