Multiply the masses by the respective distances:
(12 kg) (2 m) = 24 J
(25 kg) (1 m) = 25 J
so the heavier bag takes more work to lift, and (b) is the answer.
(d) is technically correct if the sacks are carrying different contents whose masses are not equal, but since we don't know what's inside each sack, assume 12 kg and 25 kg are the masses of each sack *and* their contents.
Which picture are you talking about?
Answer:
In the picture
Explanation:
I hope that it's a clear solution and explanation, hope that helps.
Answer:
<u>We are given:</u>
displacement (s) = 130 m
acceleration (a) = -5 m/s²
final velocity (v) = 0 m/s [the cars 'stops' in 130 m]
initial velocity (u) = u m/s
<u>Solving for initial velocity:</u>
From the third equation of motion:
v² - u² = 2as
replacing the variables
(0)² - (u)² = 2(-5)(130)
-u² = -1300
u² = 1300
u = √1300
u = 36 m/s
Answer:
68.5 meters
Explanation:
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 3.74 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0) (3.74) + ½ (9.8) (3.74)²
Δy = 68.5
The egg fell 68.5 meters.
