Complete question:
A diver is 10 m below the surface of water. Calculate the pressure the fluid exerted on the diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is 1000 kg/m3. Answer in units of Pa. Show your work.
Answer:
Tthe pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa
Explanation:
Given;
density of water, ρ = 1000 kg/m³
diver's position below the surface of the water, h = 10 m
acceleration due to gravity, g = 9.8 m/s²
Let the atmospheric pressure, P₀ = 101325 Pa
The pressure 10 m below the surface of the water is calculated as;
P = P₀ + ρgh
P = 101325 Pa + (1000 x 9.8 x 10)Pa
P = 199325 Pa
P = 1.99 x 10⁵ Pa.
Therefore, the pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa
Answer:
R₂ / R₁ = D / L
Explanation:
The resistance of a metal is
R = ρ L / A
Where ρ is the resistivity of aluminum, L is the length of the resistance and A its cross section
We apply this formal to both configurations
Small face measurements (W W)
The length is
L = W
Area
A = W W = W²
R₁ = ρ W / W² = ρ / W
Large face measurements (D L)
Length L = D= 2W
Area A = W L
R₂ = ρ D / WL = ρ 2W / W L = 2 ρ/L
The relationship is
R₂ / R₁ = 2W²/L
Answer
A. the work done on the refrigerant in each cycle is 105kJ
B the coefficient of performance of the refrigerator is 4.8
Explanation
Given data
Work done at high temperature T2 Qh=610kJ
Work done at low temperature T1 Ql=505kJ
We know that the net work done by the refrigerator is expressed as
Wnet= Qh-Ql
=610-505
=105kJ
Also we know that the coefficient of performance is expressed as
COP= Ql/Wnet
COP= 505/105
= 4.8
Answer:
Explanation:
The image is real light rays actually focus at the image location). As the object moves towards the mirror the image location moves further away from the mirror and the image size grows (but the image is still inverted).
The components of the net force on the cart is determined as 67.66 N.
<h3>
Component of net force on the cart</h3>
The component of net force on the cart is determined by resolving the forces into x and y -components.
T1 = 30 N
T2 = 40 N
T1x = -30cos(0) = 30 N
T1y = 30sin(0) = 0
T2x = 40 x cos(30) = 34.64 N
T2y = 40 x sin(3) = 20 N
∑X = 30 N + 34.64 N = 64.64 N
∑Y = 0 + 20 N = 20 N
<h3>Resultant force</h3>
R = √(64.64² + 20²)
R = 67.66 N
Learn more about net force here: brainly.com/question/25239010
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