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Tcecarenko [31]
3 years ago
13

In the game of economics, goods are objects that fulfill peoples needs and ____.

Chemistry
1 answer:
Evgen [1.6K]3 years ago
4 0

Goods are objects that fulfill peoples needs and wants.


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How many moles of sulfur dioxide are held inside a 37.4L canister at a pressure of 0.55 atm and a temperature of 45.0 C ?
Anna35 [415]
PV=nRT n=PV/RT
R=.0821 atm x L
Mol x K
T=318K
P=.55atm
V=37.4L

n= (.55atm) (37.4L) /
.0821atm x L (318k)
mol x K
n= .79 mol of sulfur dioxide
3 0
4 years ago
A different student is given a 10.0g sample labeled CaBr2 that may contain an inert (nonreacting) impurity. Identify a quantity
Hunter-Best [27]

Answer:

Explanation:

It is density.

I do hope I helped you! :)

5 0
3 years ago
A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce
Leno4ka [110]

Answer:

The answers to the questions are;

a. The entropy of sublimation for carbon dioxide (the system) is  

134.07 J/Kmol.

b. The entropy of the universe for this reversible process is 376 J/K.

Explanation:

Entropy of sublimation is the entropy change experienced following the transformation of a mole of solid to vapor at  the temperature where the sublimation is taking place

a. We note that the mass of the solid CO₂ = 389 g

Molar mass of CO₂ = 44.01 g/mol

Number of moles of CO₂ in the sculpture = Mass/(Molar mass)

= (389 g)/(44.01 g/mol) = 8.84 Moles

Entropy of sublimation is given by

ΔS_{sublimation} = S_{vapor} - S_{solid} = \frac{\Delta H_{sublimation}}{T}

Where:

ΔH_{sublimation}  = 26.1 KJ/mol

T = Temperature = –78.5°C = ‪194.65‬ K

Therefore the amount of heat required to cause the 389 g of dry ice to sublime =    26.1 KJ/mol  × 8.84 Moles = 230.695 KJ

Therefore the entropy of sublimation = ΔS_{sublimation} = \frac{230.695 KJ}{194.65 K}

= 1.185 KJ/K

= 1185 J/K = 1185/8.84 J/Kmol = 134.07 J/Kmol

b. The entropy of the universe is given by;

ΔS_{universe} = \Delta S_{system} + ΔS_{surrounding}  

If the heat absorbed by the system is the same as the heat given off by the surrounding, then we have;

ΔS_{universe} = \frac{Q}{ T_{system}}  -\frac{Q}{T_{surrounding}}  

                =1.185 KJ/K - -\frac{230.695 KJ}{285.15K} = 1.185 KJ/K - 0.809 KJ/K = 0.376 KJ/K

= 376 J/K.

7 0
3 years ago
If you have 100.0ml of a 30.0% aqueous solution of ethanol, what volume of ethanol is in the solution?
Verdich [7]
Percent by volume is equal to the volume of the solute over the total volume of the solution times 100%. Therefore,

30 = volume of ethanol / 100 mL x 100
volume of ethanol = 30 mL

Hope this answers the question. Have a nice day.

4 0
4 years ago
Read 2 more answers
Which is an example of a solution? A. sand B. salad C. carbon D. seawater
Trava [24]
 Again, I believe the answer would be D. seawater.
7 0
4 years ago
Read 2 more answers
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