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3 years ago

Which type of bond is present in hydrogen sulfide (H2S)? The table of electronegativities is given

Chemistry

2 answers:

miv72 [106K]3 years ago

4 0

Answer:

nonpolar covalent

Explanation:

is answer on plato

o-na [289]3 years ago

3 0

Bonds formed between atoms can be classified as ionic and covalent

Ionic bonds are formed between atoms that have a high difference in the electronegativity values.

In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds. If the atoms have very similar electronegativities, they form non-polar covalent bonds.

In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).

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Calculate the pH of a 0.0150 M HNO3 solution. Assume HNO3

stellarik [79]

Answer: 1.824

Explanation: facts

4 0

3 years ago

A species that is isoelectronic with the nitrate ion and hence would have the same shape is [1] [2] [3] [4] [5] sulphur trioxide

Bumek [7]

Answer:

[1] sulphur trioxide

Explanation:

Isoelectronic species have the same number of valence electrons.

Valence electrons in nitrate (NO₃⁻):

5e- (N) + (3 x 6e-)(3xO) + 1e- (charge) = 24e-

Valence electrons in sulphur trioxide (SO₃):

6e- (S) + (3 x 6e-)(3xO) = 24e-

Valence electrons in sulphite (SO₃²⁻):

6e- (S) + (3 x 6e-)(3xO) + 2e- (charge) = 26e-

Valence electrons in phosphine (PH₃):

5e- (P) + (3 x 1e-)(3xH) = 8e-

Valence electrons in water (H₂O):

6e- (O) + (2 x 1e-)(2xH) = 8e-

Valence electrons in chlorite (ClO₂⁻):

7e- (Cl⁻) + (2 x 6e-)(2xO) + 1e- (charge) = 20e-

The only species isoelectronic with nitrate is sulphur trioxide. Both have trigonal planar geoemetry.

8 0

3 years ago

For each pair below, select the sample that contains the largest number of moles. Pair A 2.50 g O2 2.50 g N2

raketka [301]

Answer:

Explanation:

Pair 2.50g of O₂ and 2.50g of N₂

The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:

Number of moles = $\frac{mass }{molarmass}$

Atomic mass of O = 16g and N = 14g

Molar mass of O₂ = 16 x 2 = 32gmol⁻¹

Molar mass of N₂ = 14 x 2 = 28gmol⁻¹

Number of moles of O₂ = $\frac{2.5}{32}$ = 0.078mole

Number of moles of N₂ = $\frac{2.5}{28}$ = 0.089mole

We see that N₂ has the largest number of moles

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