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RSB [31]
3 years ago
6

Which type of bond is present in hydrogen sulfide (H2S)? The table of electronegativities is given

Chemistry
2 answers:
miv72 [106K]3 years ago
4 0

Answer:

nonpolar covalent

Explanation:

is answer on plato

o-na [289]3 years ago
3 0

Bonds formed between atoms can be classified as ionic and covalent

Ionic bonds are formed between atoms that have a high difference in the electronegativity values.

In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds.  If the atoms have very similar electronegativities, they form non-polar covalent bonds.

In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).

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solubility of gas solutes in water as temperature increases such as CO2 or O2 gas and explain why using the collision theory.
ludmilkaskok [199]

Answer:

See explanation

Explanation:

When a substance is heated, its average kinetic energy increases as the molecules move faster owing to the supply of energy. The solvent molecules are able to collide more frequently with the solute molecules and dislodge them so that the solute can dissolve in the solvent.

However, when a gaseous solute is dissolved in a liquid; as the temperature is increased and solvent molecules are able to collide more frequently with the solute molecules and dislodge them, gas molecules dissolved in the liquid are more likely to escape to the gas phase and not return due to the increase in their kinetic energy.

Hence, solubility of gas solutes in water decreases as temperature increases.

7 0
3 years ago
Use the de Broglie's Wave Equation to find the wavelength of an electron moving at 7.3 × 106 m/s. Please show your work. Note: h
ad-work [718]

Answer:

\lambda=9.96\times 10^{-11}\ m

Explanation:

The expression for the deBroglie wavelength is:

\lambda=\frac {h}{m\times v}

Where,  

\lambda is the deBroglie wavelength  

h is Planck's constant having value 6.62607\times 10^{-34}\ Js

m is the mass of electron having value 9.11\times 10^{-31}\ kg

v is the speed of electron.

Given that v = 7.3\times 10^6\ m/s

Applying in the equation as:

\lambda=\frac {h}{m\times v}

\lambda=\frac{6.62607\times 10^{-34}}{9.11\times 10^{-31}\times 7.3\times 10^6}\ m

\lambda=\frac{10^{-34}\times \:6.626}{10^{-25}\times \:66.503}\ m

\lambda=\frac{6.626}{10^9\times \:66.503}\ m

\lambda=9.96\times 10^{-11}\ m

6 0
3 years ago
How many moles are in 442.8 g of strontium carbonate (SrCO3)?
GuDViN [60]

Answer:

3 moles

Explanation:

SrCO3

Mass = 442.8g

Molar mass = (87.6 + 12 * [16*3]) = 147.6g/mol

Number of moles = mass / molar mass

Number of moles = 442.8 / 147.6

Number of moles = 3

7 0
3 years ago
8. The time period of artificial satellite in a circular orbit of radius R is T. The radius of the orbit in which time period is
Elena-2011 [213]

Explanation:

It is given that,

The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

T^2\propto R^3

The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3

(\dfrac{T}{8T})^2=(\dfrac{R}{R'})^3  

\dfrac{1}{64}=(\dfrac{R}{R'})^3

R'=4\times R

So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.  

4 0
3 years ago
To objects (A and B) of the same temperature are in contact with each other? Which statement is true.
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5 0
3 years ago
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