Hello!
Find the Energy of the Photon by Planck's Equation, given:
E (photon energy) =? (in Joule)
h (Planck's constant) = 
f (radiation frequency) = 
Therefore, we have:
I Hope this helps, greetings ... DexteR! =)
Answer:
-2.86x10³ kJ
Explanation:
The enthalpy of a reaction (ΔH) is defined as the heat produced or consumed by a reaction. In the reaction:
2 C₂H₆(g) + 7 O₂(g) → 4 CO₂(g) + 6 H₂O(g)
The ΔH is the heat envolved in the reaction per 2 moles of C₂H₆. 1.43x10³ kJ are involved when 1 mole reacts. Thus, when 2 moles react, involved heat is:
1.43x10³ kJ ₓ 2 = <em>2.86x10³ kJ</em>. As the reaction is a combustion reaction (Produce CO₂ and H₂O), the heat involved in the reaction is <em>PRODUCED, </em>that means ΔH is negative, <em>-2.86x10³ kJ</em>
<span>The molar mass is 169.09
304.3g/169.09g = 1.799mol which rounds to 1.800 mol</span>
Answer: 850.0 g/min.
Explanation:
- The rate of the reaction = (ΔC/Δt) where,
ΔC is the change in concentration of reactants or products.
Δt is the change in time of the reaction proceeding.
- The rate is needed to be calculated in (g/min).
- We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).
- mass (g) = n x molar mass,
- n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.
- m = 1.5 x 283.88 = 425.82 g.
- ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.
- The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.
<em>can be approximated to 850.0 g/min.</em>
