180 ÷3 = 60 ° (angles on a straight line equals to 180 ° )
a+b+60 =180°
a+ b= 180 ° - 60° = 120°
(a+b) are 2 variables
so 120 ÷2 =60 °
therefore a and b =60 °
c +b+ 60° = 180° ( co - interior angles are supplementary angles )
c+60° +60° =180°
c +120° =180°
c =180°-120°
c=60 °
d=60° (alternate angles are equal )
or
c+b+d=180°
60° +60° + d = 180°
d=180°-120°
d=60°
Your answer is 160
2 times Negative 8 plus 5 times Negative 2 is 160 cause the negatives cancel out
The length of AC is 16 km.
Solution:
Given data:
AB = c = 14 km, ∠A = 30° and ∠B = 89°
AC = b = ?
<u>Let us first find angle C:</u>
<em>Sum of all angles in a triangle = 180°</em>
m∠A+ m∠B + m∠C = 180°
30° + 89° + m∠C = 180°
119° + m∠C = 180°
Subtract 119° from both sides, we get
m∠C = 61°
<u>To find the length of AC:</u>
<em>Using sine formula:</em>

Substitute the given values in the formula.

Multiply by sin 89° on both sides.



The length of AC is 16 km.
The answer is 45 because I just had this question