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3 years ago

In order to safely conduct any experiment in the laboratory, it is crucial that you

1 answer:

3 0

Lab Safety Rules:

Report all accidents, injuries, and breakage of glass or equipment to instructor immediately. Keep pathways clear by placing extra items (books, bags, etc.) on the shelves or under the work tables. If under the tables, make sure that these items can not be stepped on. Long hair (chin-length or longer) must be tied back to avoid catching fire. Wear sensible clothing including footwear. Loose clothing should be secured so they do not get caught in a flame or chemicals.Work quietly — know what you are doing by reading the assigned experiment before you start to work. Pay close attention to any cautions described in the laboratory exercises Do not taste or smell chemicals. Wear safety goggles to protect your eyes when heating substances, dissecting, etc. Do not attempt to change the position of glass tubing in a stopper. Never point a test tube being heated at another student or yourself. Never look into a test tube while you are heating it.Unauthorized experiments or procedures must not be attempted.Keep solids out of the sink. Leave your work station clean and in good order before leaving the laboratory. Do not lean, hang over or sit on the laboratory tables. Do not leave your assigned laboratory station without permission of the teacher. Learn the location of the fire extinguisher, eye wash station, first aid kit and safety shower. Fooling around or "horse play" in the laboratory is absolutely forbidden. Students found in violation of this safety rule will be barred from participating in future labs and could result in suspension. Anyone wearing acrylic nails will not be allowed to work with matches, lighted splints, Bunsen burners, etc. Do not lift any solutions, glassware or other types of apparatus above eye level. Follow all instructions given by your teacher.Learn how to transport all materials and equipment safely. No eating or drinking in the lab at any time!

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The open-circuit voltage of a car battery is measured to be 12 V. During engine startup, the battery delivers 10 A to the starte

dmitriy555 [2]

Answer:

- the Thevenin equivalent circuit for the battery is uploaded below

- the battery delivered 117 watts of power to the starter motor

Explanation:

Given the data in the equation

diagram of the Thevenin equivalent circuit for the battery is uploaded below.

Current I = 10 A

Voltage 1 = 12 V

voltage 2 = 11.7 v

R = (V1 - V2) / I

R = (12-11.7)/10

R = 0.3 / 10

R = 0.03Ω

Thevenin equivalent circuit

$R_{L}$ = V2 / I = 11.7 / 10

$R_{L}$ = 1.17Ω

so, power delivered to the starter motor will be;

p = (V2)² / $R_{L}$

P = ( 11.7 V )² / 1.17Ω

p = 136.89 / 1.17

p = 117 watts

Therefore, the battery delivered 117 watts of power to the starter motor

8 0

3 years ago

Which level of protein structure is formed by the weak bonds between oxygen and hydrogen atoms within the polypeptide backbone.

vredina [299]

Answer:

Secondary structure

The secondary structure arises from the hydrogen bonds formed between atoms of the polypeptide backbone. The hydrogen bonds form between the partially negative oxygen atom and the partially positive nitrogen atom

8 0

3 years ago

An AC circuit with a total resistance of R has an rms current of I. The circuit wraps around an iron core transistor with 50 loo

zvonat [6]

Answer:

current is 13.88 A

Explanation:

given data

no of loops = 50 loops

resistance = 40 Ω

R = 15.0 Ω

I = 5.0 amp

N = 18

to find out

rms current

solution

we will apply here transformed principle that is

v(s) / v(p) = I(p) / I(s) = N(s) / N(p) ....................1

here p is primary and s is secondary

put here all these value

5 / I(s) = 18 / 50

I(s) = 250 /18

I(s) = 13.88

so current is 13.88 A

6 0

4 years ago

What is the equivalent capacitance of the three capacitors in the figure (figure 1)?

vekshin1

The equivalent capacitance of the combination is $\dfrac{1}{C} = \dfrac{1}{C_1}+\dfrac{1}{C_2}$ where C1 and C2 are the capacitance of both capacitors in series.

<h3>What is equivalent capacitor?</h3>

Let the capacitance of both capacitors be C1 and C2. For a series connected capacitors, same charge flows through the capacitors but different voltage flows through them.

Let Q be the amount of charge in each capacitors,

V be the voltage across each capacitors

C be the capacitance of the capacitor.

Using the formula Q = CV where V = Q/C... (1)

For the large capacitor with capacitance of the capacitor C1,

$Q = C_1V_1;$

$V_1 = \dfrac{Q}{C_1}...(2)$

where $V_1$ is the voltage across $C_1,$

For the small capacitor with capacitance of the capacitor $C_2$ ,

$Q = C_2V_2$ ;

$V_2 = \dfrac{Q}{C_2} ... (3)$

where $V_2$ is the voltage across $C_2$ ,

Total voltage V in the circuit will be;

$V = V_1+V_2... (4)$

Substituting equation 1, 2 and 3 in equation 4, we have;

$\dfrac{Q}{C} = \dfrac{Q}{C_1} +\dfrac{ Q}{C_2}$

$\dfrac{Q}{C} = Q({\dfrac{1}{C_1}+\dfrac{1}{C_2})$

Since change Q is the same for both capacitors since they are in series, they will cancel out to finally have;

$\dfrac{1}{C} = ({\dfrac{1}{C_1}+\dfrac{1}{C_2})$

This gives the equivalent capacitance of the combination.

To know more about equivalence capacitance follow

brainly.com/question/5626146

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7 0

2 years ago

The fine structure for hydrogen atom is

pochemuha

Answer:

When the familiar red spectral line of the hydrogen spectrum is examined at very high resolution, it is found to be a closely-spaced doublet. This splitting is called fine structure and was one of the first experimental evidences for electron spin.

Explanation:

5 0

3 years ago