A deviated nasal septum occurs when the partition between the two nostrils is pushed to one side, leading to a partially obstructed airway in one nostril.
Answer:
Qsinθ/4πε₀R²θ
Explanation:
Let us have a small charge element dq which produces an electric field E. There is also a symmetric field at P due to a symmetric charge dq at P. Their vertical electric field components cancel out leaving the horizontal component dE' = dEcosθ = dqcosθ/4πε₀R² where r is the radius of the arc.
Now, let λ be the charge per unit length on the arc. then, the small charge element dq = λds where ds is the small arc length. Also ds = Rθ.
So dq = λRdθ.
Substituting dq into dE', we have
dE' = dqcosθ/4πε₀R²
= λRdθcosθ/4πε₀R²
= λdθcosθ/4πε₀R
E' = ∫dE' = ∫λRdθcosθ/4πε₀R² = (λ/4πε₀R)∫cosθdθ from -θ to θ
E' = (λ/4πε₀R)[sinθ] from -θ to θ
E' = (λ/4πε₀R)[sinθ]
= (λ/4πε₀R)[sinθ - sin(-θ)]
= (λ/4πε₀R)[sinθ + sinθ]
= 2(λ/4πε₀R)sinθ
= (λ/2πε₀R)sinθ
Now, the total charge Q = ∫dq = ∫λRdθ from -θ to +θ
Q = λR∫dθ = λR[θ - (-θ)] = λR[θ + θ] = 2λRθ
Q = 2λRθ
λ = Q/2Rθ
Substituting λ into E', we have
E' = (Q/2Rθ/2πε₀R)sinθ
E' = (Q/θ4πε₀R²)sinθ
E' = Qsinθ/4πε₀R²θ where θ is in radians
Answer:
a = 1 m/s²
Explanation:
given,
mass of the person = 60 Kg
Net External force exerted = 90 N
force of friction opposing the motion = 30 N
acceleration of the box = ?
Net force = External force applied - frictional force
Net force = 90 - 30
net force = 60 N
we know
F = mass x acceleration
60 = 60 x a
a = 1 m/s²
acceleration of the box is equal to a = 1 m/s²
Answer:
2.5 mm
Explanation:
It's just big enough for red and blue to fall through but small enough that yellow will stay in
Answer:
In first class lever the fulcrum lies between the effort and the load the effort lies on the left side and load lies on the right side .
Explanation:
hope this helps
