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3 years ago

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A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, a

ssuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit?

1 answer:

svetlana [45]3 years ago

4 0

Sphere surface area is A=4pi*r^2. So r is sqrt(A/4pi)
r=4cm. So d=8cm

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Function 1: y = 4x + 5 Function 2: The line passing through the points (1, 6) and (3, 10). Which of these functions has the grea

Gwar [14]

Answer:

Step-by-step explanation:

function 1 : y = 4x + 5

In y = mx + b form, which is what ur equation is in, the slope can be found in the m position. So the slope of this function is 4.

function 2 : (1,6),(3,10)

slope = (y2 - y1) / (x2 - x1)

(1,6)...x1 = 1 and y1 = 6

(3,10)...x2 = 3 and y2 = 10

now we sub

slope = (10 - 6) / (3 - 1) = 4/2 = 2

B. Function 1, because the slope is 4 and the slope of function 2 is 2. <==

8 0

3 years ago

Read 2 more answers

Find x<br> (4+25)<br> (6x+20)<br> (3x+25)

Paraphin [41]

Answer: 15

Step-by-step explanation:

Opposite angles of a cyclic quadrilateral are supplementary, so:

$3x+25+6x+20=180\\\\9x+45=180\\\\9x=135\\\\x=\boxed{15}$

6 0

2 years ago

A store has 7 red shirts, 15 black shirts, 13 white shirts, and 5 green shirts. Select the portion of the shirts that are black.

Svetach [21]

First you must add all of the shirts together, which gives you: 40

Since 15 of those are black, then you need to put those 15 over the total number of 40, making it 15/40.

Then you must simplify by the highest number that will go into both, and since that number is 5, it will then go into 15 three times and it will go into 40 eight times.

That leaves you with the answer of: 3/8

Hope I helped and good luck on your test! Please mark as brainliest if right? :)

4 0

3 years ago

7 meters/20 minutes= x cm/2 hours

meriva

Answer:4,200

Step-by-step explanation:

4 0

3 years ago

Find the area between the graph of the function and the x-axis over the given interval, if possible.

vodomira [7]

Answer:

$A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5$

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

$A = \int_{-\infty}^1 \frac{5}{(x-2)^2}$

For this case we can use the following substitution $u = x-2$ and we have $dx = du$

$A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du$

And if we solve the integral we got:

$A= -\frac{5}{u} \Big|_a^b$

And we can rewrite the expression again in terms of x and we got:

$A = -\frac{5}{x-2} \Big|_{-\infty}^1$

And we can solve this using the fundamental theorem of calculus like this:

$A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5$

So then the integral converges and the area below the curve and the x axis would be 5.

7 0

3 years ago