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3 years ago

11

A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, a

ssuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit?

1 answer:

svetlana [45]3 years ago

4 0

Sphere surface area is A=4pi*r^2. So r is sqrt(A/4pi)
r=4cm. So d=8cm

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2 years ago

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2 years ago

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A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).

juin [17]

Answer:

A. $PR = 80.6 yd$

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Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

$PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}$

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$PR = \sqrt{4,900 + 1,600}$

$PR = \sqrt{6,500}$

$PR = 80.6 yd$ (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

PQ = |50 - 10| = 40 yd

QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

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2 years ago

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Answer:

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3 years ago

Read 2 more answers