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never [62]
3 years ago
12

A price increase from $12 to $15 find the percent of increase

Mathematics
2 answers:
Alina [70]3 years ago
7 0
Old =12
New = 15
Change =12-15 so 3

3/12
x/100 so the increase equals 4,the answer is 4%
olganol [36]3 years ago
6 0
There is a 125% increase 
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The solutions of a quadratic equation are ​-4,9 Write a related quadratic function in factored form.
Yuri [45]

Answer:

y = (x + 4)(x - 9)

Step-by-step explanation:

x = {-4, 9}

y = (x + 4)(x - 9)

3 0
3 years ago
According to the National Association of Colleges and Employers, the average starting salary for new college graduates in health
katen-ka-za [31]

Answer:

a) The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b) The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c) The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d) A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

Step-by-step explanation:

<em>a. What is the probability that a new college graduate in business will earn a starting salary of at least $65,000?</em>

For college graduates in business, the salary distributes normally with mean salary of $53,901 and standard deviation of $15,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-53901}{15000} =0.74

The probability is then

P(X>65,000)=P(z>0.74)=0.22965

The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

<em>b. What is the probability that a new college graduate in health sciences will earn a starting salary of at least $65,000?</em>

<em />

For college graduates in health sciences, the salary distributes normally with mean salary of $51,541 and standard deviation of $11,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-51541}{11000} =1.22

The probability is then

P(X>65,000)=P(z>1.22)=0.11123

The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

<em>c. What is the probability that a new college graduate in health sciences will earn a starting salary less than $40,000?</em>

To calculate the probability of earning less than $40,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{40000-51541}{11000} =-1.05

The probability is then

P(X

The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

<em />

<em>d. How much would a new college graduate in business have to earn in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences?</em>

The z-value for the 1% higher salaries (P>0.99) is z=2.3265.

The cut-off salary for this z-value can be calculated as:

X=\mu+z*\sigma=51,541+2.3265*11,000=51,541+25,592=77,133

A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

8 0
3 years ago
Write 9020000 in standard form?
dolphi86 [110]

Answer:

9.02 x 10^6

Step-by-step explanation:

hope this helps!

8 0
3 years ago
A school has a goal of getting at least 2000 boxtops.They have 8 days left to get it. At least how many do they need to collect
vova2212 [387]
They need to get at least 250 boxtops each day to meet or exceed the goal. Hope this helps!
5 0
3 years ago
Read 2 more answers
Deposit $500 4% interest 2 years
STatiana [176]

Are you looking for the amount after interest gained? If so I believe the answer would be $40.

500 x 0.04 x 2 = 40

7 0
3 years ago
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