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3 years ago

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A 500 gram mass is connected to a spring and undergoing uniform circular motion. The radius is at 14.5 cm and the applied centri

petal force is 5.88N. The velocity of the spinning mass is measured to be 1.31 m/s. Keeping the force and mass constant the radius of the bob was increased by 1 cm. What should be the expected velocity of the spinning mass at the new radius?

1 answer:

swat323 years ago

6 0

To solve the problem it is necessary to apply the concepts related to the Centripetal Force.

By definition the centripetal force is given by

$F_c = \frac{mv^2}{R}$

Our values are defined by

$m=0.5Kg\\F_c = 5.88N \\R = 0.145m+1cm = 0.155m\\v = 1.31m/s$

Therefore replacing in the equation we have to,

$F_c = \frac{mv^2}{R}$

$5.88=\frac{0.5*v^2}{0.155}$

Re-arrange to find V,

$V=\sqrt{\frac{5.88*0.155}{0.5}}$

$V= 1.35m/s$

Therefore the expected velocity of the spinning mass at the new radius is 1.35m/s

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