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Vitek1552 [10]
3 years ago
9

A 500 gram mass is connected to a spring and undergoing uniform circular motion. The radius is at 14.5 cm and the applied centri

petal force is 5.88N. The velocity of the spinning mass is measured to be 1.31 m/s. Keeping the force and mass constant the radius of the bob was increased by 1 cm. What should be the expected velocity of the spinning mass at the new radius?
Physics
1 answer:
swat323 years ago
6 0

To solve the problem it is necessary to apply the concepts related to the Centripetal Force.

By definition the centripetal force is given by

F_c = \frac{mv^2}{R}

Our values are defined by

m=0.5Kg\\F_c = 5.88N \\R = 0.145m+1cm = 0.155m\\v = 1.31m/s

Therefore replacing in the equation we have to,

F_c = \frac{mv^2}{R}

5.88=\frac{0.5*v^2}{0.155}

Re-arrange to find V,

V=\sqrt{\frac{5.88*0.155}{0.5}}

V= 1.35m/s

Therefore the expected velocity of the spinning mass at the new radius is 1.35m/s

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AURORKA [14]

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3 years ago
Answer the question based on this waveform.
Nuetrik [128]

Answer:

Cannot be determined from the given information

Explanation:

Given the following data;

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To find the amplitude of the wave;

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.

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ω is the angular frequency measured in rad/s.

t is the time period measured in seconds.

ϕ is the phase angle.

Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.

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6 0
3 years ago
a large sphere is on a horizontal field on a sunny day. at a certain time the shadow reaches out a distance of 10 m from the poi
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Since, tan (θ/2) = 1-cos(θ) / sin(θ)

we find that,

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Hence, r = 10\sqrt{5} -20

So, the radius of the sphere in meters is ,r = 10\sqrt{5} -20

Learn more about radius (r) of the sphere here;

brainly.com/question/14100787

#SPJ4

5 0
1 year ago
Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the sys
Archy [21]

Speed of particle B is 2v₀/3 m/s to the left. Particle A and particle B will always have equal speed since they experience equal forces.

<h3>Conservation of energy</h3>

The speed and direction of the particle B is determined by applying the principle of conservation of energy as follows;

K.E₁ + P.E₁ = K.E₂ + P.E₂

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At any given position, the speed of particle A and particle B will be equal, since they experience equal force and they have equal masses.

The complete question is below:

Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant. At time t=T1 particle A is observed to be traveling with speed 2vo/3 to the left. The speed and direction of motion of particle B is ?

Learn more about conservation of energy here: brainly.com/question/166559

5 0
2 years ago
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Vitek1552 [10]
We know that
Distance = speed x time
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w = 0.75 hours
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= 3.75 km
5 0
3 years ago
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