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3 years ago

Answer the question based on this waveform.

Physics

1 answer:

Nuetrik [128]3 years ago

6 0

Answer:

Cannot be determined from the given information

Explanation:

Given the following data;

Velocity = 24 m/s

Period = 3 seconds

To find the amplitude of the wave;

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.

A is the amplitude.

ω is the angular frequency measured in rad/s.

t is the time period measured in seconds.

ϕ is the phase angle.

Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.

However, the given parameters can be used to calculate the frequency and wavelength of the wave.

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Refer to the image. Calculate the magnitude of change in velocity of the cue ball.

valkas [14]

Answer:

If you add the 2 velocity vectors you get the velocity of the third vector which is the (change in) velocity of the cue ball after striking the cushion

V * 2 * cos 45 = 4 * cos 45 = 2.83 m/s

6 0

2 years ago

Please help the right answer get the Brainly and this is physical science btw

garik1379 [7]

Answer:

(1600 m east) + (800 m west) = (800m east)

Her displacement is 800 m east.

Explanation:

Displacement is the distance and direction between the starting point and ending point,regardless of the route traveled between them.

6 0

3 years ago

Calculate the speed of a dog running through a yard covering 24m in 52s

makvit [3.9K]

Answer:

0.46 m/s (meters/second)

Explanation:

speed = distance/time
speed = 24/52
speed = 0.461538462 m/s
Rounding this, we get speed = 0.46 m/s

5 0

3 years ago

The angular momentum of a flywheel having a rotational inertia of 0.200 kg · m2 about its central axis decreases from 3.80 to 0.

Bingel [31]

Answer:

14.3065 rad

-36.777 J

-28.29 W

Explanation:

$L_f$ = Final angular momentum = 0.6 kgm²/s

$L_i$ = Initial angular momentum = 3 kgm²/s

I = Moment of inertia = 0.2 kgm²

Torque is given by

$\tau=\dfrac{L_f-L_i}{t}\\\Rightarrow \tau=\frac{0.6-3.8}{1.3}\\\Rightarrow \tau=-2.46\ Nm$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2$

Initial angular speed is given by

$\omega_i=\dfrac{L_i}{I}$

Angular acceleration is given by

$\alpha=\dfrac{\tau}{I}$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=\dfrac{L_it+\dfrac{1}{2}\tau t^2}{I}\\\Rightarrow \theta=\dfrac{3.8\times 1.3+\dfrac{1}{2}\times -2.46\times 1.3^2}{0.2}\\\Rightarrow \theta=14.3065\ rad$

The angle is 14.3065 rad

Work done is given by

$W=\tau \theta\\\Rightarrow W=-2.46\times 14.95\\\Rightarrow W=-36.777\ J$

The work done on the wheel is -36.777 J

Power is given by

$P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{-36.777}{1.3}\\\Rightarrow P=-28.29\ W$

The power is -28.29 W

6 0

3 years ago

A person pushes a 15.7-kg shopping cart at a constant velocity for a distance of 25.9 m on a flat horizontal surface. She pushes

valentinak56 [21]

Answer:

a) F = 35.7 N, b) W = 846.7 J, c) W = - 846.9 J, d) W=0

Explanation:

a) For this exercise let's use Newton's second law, let's set a reference frame with the x-axis horizontally

let's break down the pushing force.

cos (-23,7) = Fₓ / F

sin (-237) = F_y / F

Fₓ = F cos 23.7 = F 0.916

F_y = F sin (-23.7) = - F 0.402

Y axis

N- W - F_y = 0

N = W + F 0.402

X axis

Fₓ - fr = 0

F 0.916 = fr

F = fr / 0.916

F = 32.7 / 0.916

F = 35.7 N

It is asked to calculate several jobs

b) the work of the pushing force

W = fx x

W = 35.7 cos 23.7 25.9

W = 846.7 J

c) friction force work

W = F x cos tea

friction force opposes movement

W = - fr x

W = - 32.7 25.9

W = - 846.9 J

d) The work of the force would gravitate, as the displacement and the force of gravity are at 90º, the work is zero

W = 0

6 0

3 years ago