I know for sure that the third one is correct
A :-) A.a.) Given - u = 0.00 m/s
v = 10.0 m/s
t = 1.5 sec
m = 75 kg
Solution -
a = v - u by t
a = 10 - 0 by 1.5
a = 10 by 1.5
a = 6.6 m/s^2
A.b.) sorry ! I don’t no how to do this question
The net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).
<h3>
Net electric force on the charges</h3>
The net electric force on the charges is calculated as follows;
F = kq₁q₂/r²
where;
- k is coulomb's constant
- q₁ and q₂ are the charges
- r is the distance between the charges
<h3>Distance between the charges</h3>
Thus, the net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).
Learn more about electric force here: brainly.com/question/17692887
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Answer:
Where the electric potential is constant, the strength of the electric field is zero.
Explanation:
As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e
Eₓ = - dV / dx ----------(i)
From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.
<em>Therefore, a constant electric potential means that electric field is zero.</em>
Im guessing it's (a) since the numbers go in chronological order and you read the periodic table left to right
