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coldgirl [10]
2 years ago
15

Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the sys

tem of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant
Physics
2 answers:
Archy [21]2 years ago
5 0

Speed of particle B is 2v₀/3 m/s to the left. Particle A and particle B will always have equal speed since they experience equal forces.

<h3>Conservation of energy</h3>

The speed and direction of the particle B is determined by applying the principle of conservation of energy as follows;

K.E₁ + P.E₁ = K.E₂ + P.E₂

\frac{1}{2} Mv^2_A + \frac{G}{r^2} = \frac{1}{2} Mv^2_B + \frac{G}{r^2} \\\\ \frac{1}{2} Mv^2_A = \frac{1}{2} Mv^2_B\\\\v^2_A = v^2_B\\\\v_A = v_B

v_B = \frac{2v_0}{3}  \ m/s \ to \ the \ left

At any given position, the speed of particle A and particle B will be equal, since they experience equal force and they have equal masses.

The complete question is below:

Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant. At time t=T1 particle A is observed to be traveling with speed 2vo/3 to the left. The speed and direction of motion of particle B is ?

Learn more about conservation of energy here: brainly.com/question/166559

Trava [24]2 years ago
3 0

Answer:

Explanation:

the linear momentum is conserved MiVi=MaVa+MbVb

MV0=2V0M/3+MVb

Vb=V0/3

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coldgirl [10]
Wrongggggggggggggggggggg
4 0
3 years ago
Read 2 more answers
Given 1 inch ≡ 2.54 cm and 1 foot ≡
d1i1m1o1n [39]

Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2}  }{1^{2}in^{2} } \\2991.47[cm^{2}]

3 0
3 years ago
In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a
Novay_Z [31]

Answer:

Acceleration, a = 0.101 m/s²

Explanation:

Average speed = total distance / total time.

At the 7.43km mark, total distance = 7.43km or 7430m

Total time = 25 * 60 s = 1500s

Average speed = 7430m/1500s = 4.95m/s

He then covers (10 - 7.43)km = 2.57 km = 2570 m

in t = 27m43.6s - 25min = 2m43.6s = 163.6 s

Then he accelerates for 60 s, and maintains this velocity V, for the remaining (163.6 - 60)s = 103.6 s.

From V = u + at; V = 4.95m/s + a *60s

Distance covered while accelerating is

s = ut + ½at² = 4.95m/s * 60s + ½ a *(60s)² = 297m + a*1800s²

Distance covered while at constant velocity, v after accelerating is

D = velocity * time

Where v = 4.95m/s + a*60s

D = (4.95m/s + a*60s) * 103.6s = 512.82m + a*6216s²

Total distance covered after initial 7.43 km, S + D = 2570 m, so

2570 m = 297m + a*1800s² + 512.82m + a*6216s²

2570 = 809.82 + a*8016

a = 809.82m / 8016s² = 0.101 m/s²

8 0
3 years ago
Jeremy stands on the edge of a cliff. He throws three identical rocks with the same speed. Rock X is thrown vertically upward, r
Neko [114]

Answer:

All the three rocks will hit the ground with same speed.

Explanation:

For rocks X and Z, motion is along a straight line but in case of rock Y, motion is two dimensional. Since velocity is a vector it will be difficult for us to calculate the final velocity in each case. So we should find a way to solve this problems using a scalar which is related to velocity. The best and easy to use scalar related to velocity is kinetic energy. Since there is no air resistance, the total mechanical energy of the stone remains the same. Therefore we can use the concept of conservation of mechanical energy to solve this problem.

i.e. initial mechanical energy = final mechanical energy

let us take the edge of the cliff as initial position and ground as the final position.

We know that

Mechanical energy = Kinetic energy + Potential energy

Initial Mechanical energy = Initial Kinetic energy + Initial Potential energy

we know that

Potential energy = mgh

where,

m = mass of the body

g = acceleration due to gravity

h = height from ground

All the three rocks are identical and are thrown from same height. Therefore m and h are same for all the three which implies that the initial potential energy for all the three rocks is same.

Similarly, we know that

Kinetic energy = \frac{1}{2} mv^{2}

where,

m = mass of the body

v = velocity of the body

Since all the rocks are thrown with same speed, v is same for all the rocks. Thus initial kinetic energy is also same for all.

Since initial kinetic energy and Initial Potential energy is same for all the three, Initial Mechanical energy is also same for them.

Next let us consider the final position. At the ground h = 0. Therefore final potential energy of all the three rocks is 0. Thus they will be having only kinetic energy.

By conservation of mechanical energy,

initial mechanical energy = final mechanical energy

i.e.  Initial Kinetic energy + Initial Potential energy =  final Kinetic energy + final Potential energy

final potential energy = 0

thus,

Initial Mechanical energy = Initial Kinetic energy + Initial Potential energy = final Kinetic energy

Initial Mechanical energy = final Kinetic energy

Since Initial Mechanical energy is same for all the three, by the above equation final Kinetic energy is also same for all the three. Since here, kinetic energy is the function of only velocity, final velocity is also same for all the three rocks.

i.e. all the three rocks will hit the ground with same speed.

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3 years ago
What process modifies light waves to vibrate in a single plane
AnnyKZ [126]
This process is called polarization.
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