Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the sys
2 answers:
Speed of particle B is 2v₀/3 m/s to the left. Particle A and particle B will always have equal speed since they experience equal forces.
<h3>Conservation of energy</h3>The speed and direction of the particle B is determined by applying the principle of conservation of energy as follows;
K.E₁ + P.E₁ = K.E₂ + P.E₂
At any given position, the speed of particle A and particle B will be equal, since they experience equal force and they have equal masses.
The complete question is below:
Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant. At time t=T1 particle A is observed to be traveling with speed 2vo/3 to the left. The speed and direction of motion of particle B is ?
Learn more about conservation of energy here: brainly.com/question/166559
You might be interested in
Answer:
2991.47 [cm^2]
Explanation:
To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:
Answer:
All the three rocks will hit the ground with same speed.
Explanation:
For rocks X and Z, motion is along a straight line but in case of rock Y, motion is two dimensional. Since velocity is a vector it will be difficult for us to calculate the final velocity in each case. So we should find a way to solve this problems using a scalar which is related to velocity. The best and easy to use scalar related to velocity is kinetic energy. Since there is no air resistance, the total mechanical energy of the stone remains the same. Therefore we can use the concept of conservation of mechanical energy to solve this problem.
i.e. initial mechanical energy = final mechanical energy
let us take the edge of the cliff as initial position and ground as the final position.
We know that
Mechanical energy = Kinetic energy + Potential energy
Initial Mechanical energy = Initial Kinetic energy + Initial Potential energy
we know that
Potential energy = mgh
where,
m = mass of the body
g = acceleration due to gravity
h = height from ground
All the three rocks are identical and are thrown from same height. Therefore m and h are same for all the three which implies that the initial potential energy for all the three rocks is same.
Similarly, we know that
Kinetic energy =
where,
m = mass of the body
v = velocity of the body
Since all the rocks are thrown with same speed, v is same for all the rocks. Thus initial kinetic energy is also same for all.
Since initial kinetic energy and Initial Potential energy is same for all the three, Initial Mechanical energy is also same for them.
Next let us consider the final position. At the ground h = 0. Therefore final potential energy of all the three rocks is 0. Thus they will be having only kinetic energy.
By conservation of mechanical energy,
initial mechanical energy = final mechanical energy
i.e. Initial Kinetic energy + Initial Potential energy = final Kinetic energy + final Potential energy
final potential energy = 0
thus,
Initial Mechanical energy = Initial Kinetic energy + Initial Potential energy = final Kinetic energy
Initial Mechanical energy = final Kinetic energy
Since Initial Mechanical energy is same for all the three, by the above equation final Kinetic energy is also same for all the three. Since here, kinetic energy is the function of only velocity, final velocity is also same for all the three rocks.
i.e. all the three rocks will hit the ground with same speed.