Answer it will move slower:
Explanation: cause the force that’s opposite of it
You should calculate 40 kg and the radius 3mm.
Answer:
Explanation:
<u>Displacement</u>
It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.
The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is
Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by
Finally, he drives 9.5 km 35° north of east.
The total displacement is
The direction can be calculated with
Answer:
To increase kinetic friction, the amount of fine water droplets sprayed before the game is limited.
To reduce kinetic friction. increase the amount of fine water droplets during pregame preparation and sweeping in front of the curling stones.
Explanation:
In curling sports, since the ice sheets are flat, the friction on the stone would be too high and the large smooth stone would not travel half as far. Thus controlling the amount of fine water droplets sprayed before the game is limited pregame is necessary to increase friction.
On the other hand, reducing ice kinetic friction involves two ways. The first way is adding bumps to the ice which is known as pebbling. Fine water droplets are sprayed onto the flat ice surface. These droplets freeze into small "pebbles", which the curling stones "ride" on as they slide down the ice. This increases contact pressure which lowers the friction of the stone with the ice. As a result, the stones travel farther, and curl less.
The second way to reduce the kinetic friction is sweeping in front of the large smooth stone. The sweeping action quickly heats and melts the pebbles on the ice leaving a film of water. This film reduces the friction between the stone and ice.
To solve this problem it is necessary to apply the kinematic equations of linear and angular motion, as well as the given definitions of the period.
Centripetal acceleration can be found through the relationship
Where
v = Tangential Velocity
R = Radius
At the same time linear velocity can be expressed in terms of angular velocity as
Where,
R = Radius
Angular Velocity
PART A) From this point on, we can use the values used for the period given in the exercise because the angular velocity by definition is described as
T = Period
So replacing we have to
Since 
Then the radius in meters would be
Then the centripetal acceleration would be
From the result obtained, considering that it is an unimaginably low value of an order of less than 
it is possible to conclude that it supports the assertion on the inertial reference frame.
