Answer:
- There was a constant acceleration at 0 to 10s
- There was a zero acceleration at 10 to 25s
- There was a constant deceleration at 25 to 30s
Explanation:
<em>See attachment for complete question.</em>
Solving (a): What happens at 0s to 10s
There was a constant acceleration and this is proven below.
At time 0, velocity = 15
At time 10, velocity = 30
This is represented as:


Acceleration (A) is the rate of change of velocity against time.
So:




<em>Since the acceleration is positive, then it shows a constant acceleration.</em>
Solving (b): What happens at 10s to 25s
There was a zero acceleration and this is because the velocity do not change.
See proof below
At time 10, velocity = 30
At time 25, velocity = 30
This is represented as:


Acceleration (A) is the rate of change of velocity against time.
So:




Solving (c): What happens at 25s to 30s
There was a constant deceleration and this is proven below.
At time 25, velocity = 30
At time 30, velocity = 0
This is represented as:


Acceleration (A) is the rate of change of velocity against time.
So:




<em>Since the acceleration is negative, then it shows a constant deceleration</em>