Answer:
The final temperature is 348.024°C.
Explanation:
Given data:
Specific heat of copper = 0.385 j/g.°C
Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)
Mass of copper = 62.0 g
Initial temperature T1 = 26.7°C
Final temperature T2 = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
Q = m.c. ΔT
7670 J = 62.0 g × 0.385 j/g °C ×( T2- 26.7 °C
)
7670 J = 23.87 j.°C ×( T2- 26.7 °C
)
7670 J / 23.87 j/°C = T2- 26.7 °C
T2- 26.7 °C = 321.324°C
T2 = 321.324°C + 26.7 °C
T2 = 348.024°C
The final temperature is 348.024°C.
0.000125
Explanation:
if you remember King Henry Died Drinking Chocolate Milk= K H D & D C M
find what your converting to and move the decimal that many times in that direction.
Answer:
M.Mass = 120 g/mol
Explanation:
Data Given:
Volume = V = 0.0650 L
Temperature = T = 547 °C = 820.15 K
Pressure = P = 70.5 kPa = 0.695 atm
Gas Constant = R = 0.082057 L.atm.mol⁻¹.K⁻¹
Formula Used:
Assuming that the gas is ideally then according to ideal gas equation,
P V = n R T
Solving for n,
n = P V / R T
Putting Values,
n = (0.695 atm × 0.0650 L) ÷ (0.082057 L.atm.mol⁻¹.K⁻¹ × 820.15 K)
n = 6.71 × 10⁻⁴ moles
Now, Knowing that,
Moles = Mass / M.Mass
Or,
M.Mass = Mass / Moles
Putting values,
M.Mass = 8.06 × 10⁻² g / 6.71 × 10⁻⁴ mol
M.Mass = 120 g/mol
The traditional method is to heat the compound in an oven, on a hot plate or over a Bunsen burner. Waters of hydration are loosely bound in the compound and can be driven off at temperatures below the melting point of the compound. So the answer is heating.
Answer:
Number of atoms =1.806×10²⁴
Explanation:
You have the number of moles of Carbon tetrachloride which is n=3
And you are looking for number of atoms that are in the sample, which are represented by the letter "N"
The formula that has both number of moles(n) and number of atoms(N) is written as n=N/Na
Na is called the Avogadros number and it is equal to 6.08×10²³, it never changes(it is a constant)
So you will substitute the number of moles and the avogadros number to you formula, and the only unknown will be the number of atoms which you are looking for
- n=N/Na
- 3=N(6.02×10²³)
- N=1.806×10²⁴ atoms of CCl
NB: N does not represent the number of atoms only. It may also represent the number of particles or molecules...