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11111nata11111 [884]

3 years ago

11

For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s? Recall that accel

eration is the derivative of velocity with respect to time.

1 answer:

Karo-lina-s [1.5K]3 years ago

4 0

I think its half of pie so you divid that by 3.14 .

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Which best describes the body in terms of simple machines?

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kumpel [21]

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What is the net work done on the 20kg block while it moves the 4 meters?

Vinil7 [7]

Answer:

The answer to your question is 784.8 J. None of your answer, did you forget some information?

Explanation:

Data

mass = 20 kg

distance = 4 m

work = ?

Formula

Work = force x distance

Force = mass x gravity

Process

1.- Calculate the weight of the block

Weight = 20 x 9.81

Weight = 196.2 N

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4 years ago

A car begins at rest (0 velocity), 5 seconds later it is travelling at 20 meters/per second. What was the acceleration of the ve

klasskru [66]

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4 0

3 years ago

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Find the wavelength of a photon which has 500.0 eV of energy.

jekas [21]

Answer:

2.5 x 10⁻⁹ m

Explanation:

E = Energy of photon = 500 eV = 500 x 1.6 x 10⁻¹⁹ J

c = speed of photon = 3 x 10⁸ m/s

λ = wavelength of photon = ?

Energy of photon is given as

$E = \frac{hc}{\lambda }$

inserting the values

$500\times 1.6\times 10^{-19} = \frac{(6.63\times 10^{-34})(3\times 10^{8})}{\lambda }$

λ = 2.5 x 10⁻⁹ m

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4 years ago