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11111nata11111 [884]

2 years ago

11

For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s? Recall that accel

eration is the derivative of velocity with respect to time.

1 answer:

Karo-lina-s [1.5K]2 years ago

4 0

I think its half of pie so you divid that by 3.14 .

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Which statement best explains why atoms form chemical bonds with other atoms?

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2 years ago

As shown in the diagram below, a 1 kg rock tied to a rope is

Tatiana [17]

Answer:

Explanation:

Angular momentum has a formula of L = mvr. Fillingin:

L = (1.0)(5.0)(1.0)

L = 5.0 kg*m/s

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2 years ago

The driver sees that the road is empty and accelerates at 1.0 m/s2 for 5.0 s. what can you determine about the truck's motion us

vekshin1

kinematic equation

v=u+at

v-u=at

v-u = 1x5

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2 years ago

Steam is leaving a pressure cooker whose operating pressure is 20 psia. It is observed that the amount of liquid in the cooker h

Debora [2.8K]

Answer:

a) 34.05ft/s

b).1156.2BTU/lbm

c) 2.04BTU/s

Explanation:

Amount of liquid that has evaporated, m = ◇Vliq/ Vf

We replace the values to make conversion

m = (0.6gal/ 0.01683ft^3/lbm) × (0.13368ft^3/1gal)

m = 4.755lb

The mass flow rate of exit steam is given by:

m' = m/◇t

We replace values to make conversion

m' =( 4.766lb/45min) = 0.1059lb/min × 1min/60s

m' = 0.001765lb/s

The exit velocity V = m'/pA = m'Vg/A

We replace values to make conversion

V =[ (0.001765lbm/s)(20.093ft^3/lbm) /(0.15 in^2)]× (144in^2/1ft^2)

V = 34.05ft/s

b) The total and flow energies per unit mass is given by:

Eflow= Pv = h - u

We replace the values to make conversion

Eflow = 1156.2 - 1081.8

Eflow = 74.4BTU/lbm

Therefore theta= h + ke + pe

Theta approximately =h = 1156.2BTU/lbs

c) The rate at which energy is leaving the cooler by steam is given by:

Emass = m'theta

Emass = (0.001765)×(1156.2)

Emass = 2.04BTU/s

6 0

2 years ago