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2 years ago

In most circumstances, the normal force acting on an objectand

Physics

1 answer:

Lynna [10]2 years ago

4 0

Answer:

Normal Force is usually perpendicular to the movement and static friction usually means that there is no movement.

Explanation:

The work donde by any force on an object is equal to the displacement of the object multiplied by the component of the force that is in the direction of the displacement.

Normal force is usually perpendicular to the movement, so there is no component in the direction of the displacement. This is why it is zero in most circumstances.

<em>Static</em> friction on the other hand, usually means that there is no movement at all (it's static). It means that there is no displacement between the object and ground (in most cases). If there is no displacement, there is no work.

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Skater 1 has a mass of 105.0 kg and a velocity of 2.0 m/s to the left. He

mart [117]

The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

<h3>What is velocity?</h3>

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

mu+MU = mv+MV............ Equation 1

Where:

m = mass of the first skater
M = mass of the second skater
u = initial velocity of the first skater
U = initial velocity of the second skater
v = final velocity of the first skater
V = final velocity of the second skater.

make v the subject of the equation.

v = (mu+MU-MV)/m................ Equation 2

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

m = 105 kg
u = -2 m/s
M = 71 kg
U = 5 m/s
V = -3.4 m/s.

Substitute these values into equation 2

v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
v = (-210+355+241.4)/105
v = 386.4/105
v = 3.68 m/s
v ≈ 3.7 m/s

Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Learn more about velocity here: brainly.com/question/25749514

7 0

1 year ago

A women does 80.0 joules of work when she slides a book 4.0 meters on the floor. How much force does she apply to the book

Kryger [21]

It would be 80/4 = 20 Newtons??? I think

5 0

2 years ago

According to Newton's first law of motion, what is required to make an object slow down? Enter your answer in the space provided

LenaWriter [7]

<u>Answer:</u>

According to newton's first law of motion, friction is required to make an object slow down.

<u>Explanation:</u>

According to the Newton's first law of motion, for an object to change its velocity (either a change in the magnitude or the direction), there must be a cause to it which is defined as a net external force.

For example, an object which is sliding across a table or floor slows down due to the net force of friction that is acting on that object.

5 0

2 years ago

Can someone please help?

Diano4ka-milaya [45]

I think you go to my school!

7 0

2 years ago

Starting from rest, a disk rotates about its central axis with constant angular acceleration. In 8.0 s, it rotates 35 rad.

Harman [31]

Answer:

(a) 1.093 rad/s^2

(b) 4.375 rad/s

(d) 67.845 rad

Explanation:

initial angular velocity, ωo = 0

time, t = 8s

angular displacement, θ = 35 rad

(a) Let α be the angular acceleration.

Use second equation of motion for rotational motion

$\theta =\omega _{0}t+\frac{1}{2}\alpha t^{2}$

By substituting the values

35 = 0 + 0.5 x α x 8 x 8

α = 1.093 rad/s^2

(b) The average angular velocity is defined as the ratio of total angular displacement to the total time taken .

Average angular velocity = 35 / 8 = 4.375 rad/s

Use first equation of motion for rotational motion

ω = ωo + αt

ω = 0 + 1.093 x 8 = 8.744 rad/s

(d) Let in next 5 seconds the angular displacement is θ.

$\theta =\omega _{0}t+\frac{1}{2}\alpha t^{2}$

By substituting the values

θ = 8.744 x 5 + 0.5 x 1.093 x 5 x 5

θ = 67.845 rad

8 0

3 years ago