Answer:
(a)
W_friction = 98.1 J
W_net = 550.9 J
(b)
W_friction = 98.1 J
W_net = 463.95 J
Explanation:
(a)
First, we will calculate the work done by friction:

<u>W_friction = 98.1 J</u>
Now, the work done by Eskimo will be:

W_Eskimo = 649 J
So, the net work will be:
W_net = W_{Eskimo} - W_{friction}
W_net = 649 J - 98.1 J
<u>W_net = 550.9 J</u>
<u></u>
(b)
First, we will calculate the work done by friction:

<u>W_friction = 98.1 J</u>
Now, the work done by Eskimo will be:

W_Eskimo = 562.05 J
So, the net work will be:
W_net = W_{Eskimo} - W_{friction}
W_net = 562.05 J - 98.1 J
<u>W_net = 463.95 J</u>
Answer:

Explanation:
We can use one of the kinematics equation to find the acceleration.
v = u + at
where v = final velocity, in m/s
u = initial velocity, in m/s
t = time in seconds
Given the information provided from the question,
v = 25m/s
u = 0m/s
t = 10s
Substitute these values into the kinematics equation.
25 = 0 + 10a
10a = 25
a = 25 / 10
= 