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a_sh-v [17]
2 years ago
11

The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere ​

Physics
1 answer:
spin [16.1K]2 years ago
5 0

Answer:

P = 0.0644 atm

Explanation:

Given that,

The pressure of a sample of gas is measured as 49 torr.

We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

1 atm = 760 torr

1 torr = (1/760) atm

49 torr = (49/760) atm

= 0.0644 atm

Hence, the presssure of the sample of gas is equal to 0.0644 atm.

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D. Q/2

Explanation:

See attached file

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Use the worked example above to help you solve this problem. An Eskimo returning from a successful fishing trip pulls a sled loa
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Answer:

(a)

W_friction = 98.1 J

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(b)

W_friction = 98.1 J

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Explanation:

(a)

First, we will calculate the work done by friction:

W_{friction} = \mu R = \mu W = \mu mg\\W_{friction} = (0.2)(50\ kg)(9.81\ m/s^2)\\

<u>W_friction = 98.1 J</u>

Now, the work done by Eskimo will be:

W_{Eskimo} = FdCos\theta\\W_{Eskimo} = (110\ N)(5.9\ m)Cos\ 0^o\\

W_Eskimo = 649 J

So, the net work will be:

W_net = W_{Eskimo} - W_{friction}

W_net = 649 J - 98.1 J

<u>W_net = 550.9 J</u>

<u></u>

(b)

First, we will calculate the work done by friction:

W_{friction} = \mu R = \mu W = \mu mg\\W_{friction} = (0.2)(50\ kg)(9.81\ m/s^2)\\

<u>W_friction = 98.1 J</u>

Now, the work done by Eskimo will be:

W_{Eskimo} = FdCos\theta\\W_{Eskimo} = (110\ N)(5.9\ m)Cos\ 30^o\\

W_Eskimo = 562.05 J

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2 years ago
Energy conversion from potential energy (the energy of position or composition) to kinetic energy (the energy of motion) is illu
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<h2>The following is an elaboration of the differences in potential and kinetic energies based on the diagram of the roller coaster: </h2>

  • When the coaster is in position A, the potential energy is maximum and the kinetic energy is minimum.
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5 0
2 years ago
The initial velocity of a car moving along a straight path was 0 meters/second. After 10 seconds, it reached a velocity of 25 me
maria [59]

Answer:

2.5m/s^{2}

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Given the information provided from the question,

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6 0
1 year ago
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\lambda=\frac{v}{f}=\frac{400}{200}=2[m]

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