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a_sh-v [17]
3 years ago
11

The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere ​

Physics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

P = 0.0644 atm

Explanation:

Given that,

The pressure of a sample of gas is measured as 49 torr.

We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

1 atm = 760 torr

1 torr = (1/760) atm

49 torr = (49/760) atm

= 0.0644 atm

Hence, the presssure of the sample of gas is equal to 0.0644 atm.

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0.02m/s^2

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A parallel-plate capacitor in air has a plate separation of 1.76 cm and a plate area of
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Answer:

Explanation:

Plate separation, d = 1.76 cm = 0.0176 m

Area of plates, A = 25 cm^2 = 0.0025 m^2

V = 255 V

(a) Capacitance of capacitor

C = \frac{\epsilon _0A}{d}

C = \frac{8.854\times 10^{-12}\times 0.0025}{0.0176}

C = 1.258 x 10^-12 F

charge is same before and after immersion as the battery is disconnected

q = C V

q = 1.258 x 10^-12 x 255 = 3.2 x 10^-10 C

(b)

Capacitance before, C = 1.258 x 10^-12 C

capacitance after, C' = k x C = 80 x 1.258 x 10^-12 = 100.64 x 10^-12 C

Where, k is the dielectric constant of water = 80

Potential difference after immersion, V' = V / k = 255 / 80 = 3.1875 V

(c) initial energy,

U = \frac{q^{2}}{2C}

U = \frac{(3.2\times 10^{-10})^{2}}{2\times 1.258\times 10^{-12 }}=4.07\times 10^{-8}J

Final energy

U' = \frac{q^{2}}{2C'}

U' = \frac{(3.2\times 10^{-10})^{2}}{2\times 100.64\times 10^{-12}}=5.08\times 10^{-10}J

6 0
3 years ago
A string is stretched by two equal and opposite forces F newton each then the tension in sting is?
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How is our magnetic field made?
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Hope this helps!

7 0
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Read 2 more answers
A uniform 1500-kg beam, 20.0 m long, supports a 15,000-kg printing press
Ghella [55]

Answer:

\mathbf{F_1=4.41*10^4\ N}

\mathbf{F_2 = 1.176*10^5 \ N}

Explanation:

The missing image of the figure slide is attached in below.

However, from the model, it is obvious that it is in equilibrium.

As a result, the relation of the force and the torque is said to be zero.

i.e.

\sum F = 0 and \sum \tau = 0

From the image, expressing the forces through the y-axis, we have:

F_1+F_2 = W_B + W_P \\ \\ \implies 9.8(1500+15000) \\ \\ \implies  \mathtt{1.617\times 10^5 \ N}

Also, let the force F_1 be the pivot and computing the torque to determine F_2:

Then:

F_1(0)+F_2(20.0) = 10.0W_B + 15.0W_P

F_2 = \dfrac{((10*1500)+(15*15000))*9.8}{20.0}

F_2 = 117600 \ N

\mathbf{F_2 = 1.176*10^5 \ N}

For the force equation:

F_1+F_2=1.617*10^5 \ N;

where:

F_2 = 1.176*10^5 \ N

Then:

F_1+1.176*10^5 \ N=1.617*10^5 \ N

F_1=1.617*10^5 \ N-1.176*10^5 \ N

F_1=44100\ N

\mathbf{F_1=4.41*10^4\ N}

8 0
3 years ago
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