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Aleks [24]
3 years ago
5

When the wind kicks up dust and sand, the dust grains are charged. The small grains tend to get a negative charge, and the large

grains a positive charge. The small grains are lifted higher by the wind.?
Physics
1 answer:
diamong [38]3 years ago
4 0

Answer:

Explanation:

Small grains are negatively charged by the wind while big grains is positively charged and remains at the ground . This process creates an electric field due to the presence of oppositely charged particles.

When ever electric field exists it is directed from a positive charge to a negative charge so the here electric field is towards an upwards direction.                  

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Coulomb’s Law relates which of the following?
Tom [10]
The answer is "The force between two charges and the distance separating them".

Coulomb's Law is written as:

F=k \frac{q_1q_2}{r^2}

In which F is the force felt between two charges, q_1 is the charge of one particle, q_2 is the charge of the other particle, r is the distance separating them, and k is a constant.
8 0
3 years ago
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an eco friendly hotel is under construction. Which strategies will help hotel management reach its goal of being eco friendly
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Answer:

To reach the goal to be Eco friendly, the designer must not harm the ecosystem of surrounding in any ways.

Explanation:

  • Friendly design means that the hotel must not harm the surrounding ecosystem in any way.
  • The hotels' energy consumption shall be fulfilled by the use of renewable resources like solar, wind energy, etc.
  • Proper disposal of wastage is the most important term.
  • No, chemicals are used inside the premises of the hotel for any purpose of cleaning, washing, etc.
  • The designer must place a garden with grass, trees, and flowers for the fresh air of the hotel.
3 0
3 years ago
Which wave has a disturbance that is parallel to the wave motion?
Rashid [163]
<h3><u>Answer;</u></h3>

D. Longitudinal waves

<h3><u>Explanation;</u></h3>
  • A wave is a transmission of a disturbance from one point to another. It involves the transmission of energy from a source to other points.
  • <em><u>Waves may classified as longitudinal waves or transverse waves depending on the vibration of particles relative to the wave motion.</u></em>
  • <em><u>Longitudinal waves are waves in which the vibration of particles is parallel to the direction of the wave motion, while transverse wave are types of waves in which the vibration of particles is perpendicular to the wave motion.</u></em>
  • Longitudinal waves creates regions of compressions and rarefactions, while transverse waves creates regions of maximum displacement called crests and troughs
3 0
3 years ago
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What are the two main types of energy?
djyliett [7]

Answer:

Fourth option

Explanation:

They're many different types of energy, from chemical and mechanical to heat and solar energy. But the two most basic types of energy are "kinetic and potential energy" or the fourth option. Kinetic energy is the energy an object has when it is in motion, while potential energy is the energy an object has when it's as rest. These two specific types of energies are the most basic and you can even convert them into many different types of energies, like heat or electrical energy.

Hope this helps.

7 0
2 years ago
A current of 4.00 mA flows through a copper wire. The wire has an initial diameter of 4.00 mm which gradually tapers to a diamet
lesya692 [45]

The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

The given parameters;

  • <em>Current flowing in the wire, I = 4.00 mA</em>
  • <em>Initial diameter of the wire, d₁ = 4 mm = 0.004 m</em>
  • <em>Final diameter of the wire, d₂ = 1 mm = 0.001 m</em>
  • <em>Length of wire, L = 2.00 m</em>
  • <em>Density of electron in the copper, n = 8.5 x 10²⁸ /m³</em>

<em />

The initial area of the copper wire;

A_1 = \frac{\pi d^2}{4} = \frac{\pi \times (0.004)^2}{4} =1.257\times 10^{-5} \ m^2

The final area of the copper wire;

A_2 = \frac{\pi d^2}{4} = \frac{\pi (0.001)^2}{4} = 7.86\times 10^{-7} \ m^2

The initial drift velocity of the electrons is calculated as;

v_d_1 = \frac{I}{nqA_1} \\\\v_d_1 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 1.257\times 10^{-5}} \\\\v_d_1 = 2.34 \times 10^{-8} \ m/s

The final drift velocity of the electrons is calculated as;

v_d_2 = \frac{I}{nqA_2} \\\\v_d_2 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 7.86\times 10^{-7}} \\\\v_d_2 = 3.74\times 10^{-7}  \ m/s

The change in the mean drift velocity is calculated as;

\Delta v = v_d_2 -v_d_1\\\\\Delta v = 3.74\times 10^{-7} \ m/s \ -\ 2.34 \times 10^{-8} \ m/s = 3.506\times 10^{-7} \ m/s

The time of motion of electrons for the initial wire diameter is calculated as;

t_1 = \frac{L}{v_d_1} \\\\t_1 = \frac{2}{2.34\times 10^{-8}} \\\\t_1 = 8.547\times 10^{7} \ s

The time of motion of electrons for the final wire diameter is calculated as;

t_2 = \frac{L}{v_d_1} \\\\t_2= \frac{2}{3.74 \times 10^{-7}} \\\\t_2 = 5.348 \times 10^{6} \ s

The average acceleration of the electrons is calculated as;

a = \frac{\Delta v}{\Delta t} \\\\a = \frac{3.506 \times 10^{-7} }{(8.547\times 10^7)- (5.348\times 10^6)} \\\\a = 4.38\times 10^{-15} \ m/s^2

Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

Learn more here: brainly.com/question/22406248

7 0
3 years ago
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