3 years ago

. Two people are pushing a car of mass 2000 kg.

1 answer:

5 0

Answer:

two people who are not going to be able to make it to class today because of the day and then I will be there at the house and then we can go

You might be interested in

23. If a jogger runs 100 meters west and then turns around and runs 30 meters east. What

marshall27 [118]

Answer:

Explanation:

if he goes to the west, the east is opposite so 100-30

7 0

2 years ago

Read 2 more answers

Free point cuz i cewl like dat‍♀️‍♂️

DedPeter [7]

Yes thank u teehee

.................... x

8 0

2 years ago

Read 2 more answers

Spacecrafts have landed on the surface of which planet?

ki77a [65]

I'm pretty sure its Venus!!!

7 0

3 years ago

An object with a non-zero speed must be _________.

pogonyaev

It would be either A or C if its still moving and not stopping

8 0

2 years ago

Read 2 more answers

A 100 kg box is suspended from two ropes. The "left rope makes an angle of 20" degrees with the vertical, and the right rope mak

GarryVolchara [31]

Explanation:

It is given that,

Mass of the box, m = 100 kg

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.

From the attached figure, the x and y component of forces is given by :

$T_{1x} =-T_1 cos (20)$

$T_{2x} = T_2 cos (40)$

$mg_x = 0$

$T_{1y} = T_1 sin (20)$

$T_{2y} = T_2 sin (40)$

$mg_y= -mg$

Let $R_x$ and $R_y$ is the resultant in x and y direction.

$R_x=-T_1 cos (20)+T_2 cos (40)+0$

$R_y=T_1 sin(20)+T_2 sin(40)-mg$

As the system is balanced the net force acting on it is 0. So,

$-T_1 cos (20)+T_2 cos (40)+0=0$ .............(1)

$T_1 sin(20)+T_2 sin(40)-100\times 9.8=0$ ..................(2)

On solving equation (1) and (2) we get:

$T_1=866.86\ N$ (tension on the left rope)

$T_2=1063.36\ N$ (tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.

7 0

3 years ago