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4 years ago

. Two people are pushing a car of mass 2000 kg.

Physics

1 answer:

Viktor [21]4 years ago

5 0

Answer:

two people who are not going to be able to make it to class today because of the day and then I will be there at the house and then we can go

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At a certain distance from a point charge, the potential and electric field magnitude due to that charge are 4.98 V and 12.0 V/m

Finger [1]

Answer:

1. d = 0.415 m.

2. Q = 2.285 x 10^{-10} C.

Explanation:

The electric field and potential can be found by the following equations:

$E = \frac{1}{4\pi\epsilon_0}\frac{Q}{r^2}\\V = \frac{1}{4\pi\epsilon_0}\frac{Q}{r}$

Applying these equations to the given variables yields

$E = 12 = \frac{1}{4\pi\epsilon_0}\frac{Q}{d^2}\\V = 4.98 = \frac{1}{4\pi\epsilon_0}\frac{Q}{d}$

Divide the first line to the second line:

$\frac{12}{4.98} = \frac{ \frac{1}{4\pi\epsilon_0}\frac{Q}{d^2}}{\frac{1}{4\pi\epsilon_0}\frac{Q}{d}}\\\frac{12}{4.98} = \frac{1}{d}\\d = 0.415~m$

Using this distance in either of the equations give the magnitude of the charge.

$12 = \frac{1}{4\pi\epsilon_0}\frac{Q}{(0.415)^2}\\12 = \frac{1}{4\pi (8.8\times 10^{-12})}\frac{Q}{(0.415)^2}\\Q = 2.285 \times 10^{-10}~C$

8 0

3 years ago

The gravitational force between two objects is 1600 N. What will be the gravitational force between the objects if the distance

goldfiish [28.3K]

3200 N
1600X2= 3200
It doubles so you multiply 3200 by 2

7 0

3 years ago

An oscillator consists of a block attached to a spring (k = 500 N/m). At some time t, the position (measured from the system's e

Alex_Xolod [135]

Answer:

a) $\omega = 10.407\,\frac{rad}{s}$ , b) $m = 4.617\,kg$ , c) $A = 1.355\,m$

Explanation:

a) The system have a simple armonic motion, whose position function is:

$x(t) = A\cdot \cos (\omega\cdot t + \phi)$

The velocity function is determined by deriving the position function in terms of time:

$v(t) = -\omega \cdot A \cdot \sin(\omega\cdot t + \phi)$

The acceleration function is found by deriving again:

$a(t) = -\omega^{2} \cdot A \cdot \cos (\omega\cdot t + \phi)$

Let assume that $t = 0\,s$ . The following nonlinear system is built:

$A\cdot \cos \phi = 0.660\,m$

$-\omega \cdot A \cdot \sin \phi = -12.3\,\frac{m}{s}$

$-\omega^{2}\cdot A \cdot \sin \phi = -128\,\frac{m}{s^{2}}$

System can be reduced by divinding the second and third expressions by the first expression:

$\omega \cdot \tan \phi = 18.636\,\frac{1}{s}$

$\omega^{2}\cdot \tan \phi = 193.94\,\frac{1}{s^{2}}$

Now, the last expression is divided by the first one:

$\omega = 10.407\,\frac{rad}{s}$

b) The mass of the block is:

$m = \frac{k}{\omega^{2}}$

$m = \frac{500\,\frac{N}{m} }{(10.407\,\frac{rad}{s})^{2} }$

$m = 4.617\,kg$

c) The phase angle is:

$\phi = \tan^{-1} \left(\frac{18.636\,\frac{1}{s} }{\omega} \right)$

$\phi \approx 0.338\pi$

The amplitude is:

$A = \frac{0.660\,m}{\cos 0.338\pi}$

$A = 1.355\,m$

8 0

4 years ago

Read 2 more answers

Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a wavelength of 5.9 m and

dmitriy555 [2]

The frequency of the signal is = 2.5 Hz

<h3>Calculation of frequency</h3>

The wavelength of the sonar device = 5.9 m

The velocity of the sound = 15 m/s

The frequency = ?

But the formula for the velocity of sound wave = frequency × wavelength

Male frequency the subject of formula,

f = v/ wavelength

f = 15/5.9

f = 2.5Hz

Therefore, the frequency of the signal is = 2.5Hz

Learn more about sound waves here:

brainly.com/question/1199084

#SPJ1

6 0

2 years ago

How do you measure force

snow_lady [41]

Force = mass x acceleration

It is measured in Newtons or kg*meters/sec^2

4 0

4 years ago