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BARSIC [14]
3 years ago
12

The lesser the mass, the greater the acceleration for the given value of force. Why does this happen?

Physics
1 answer:
Tju [1.3M]3 years ago
5 0
Newtons law states F=ma
so F/m=a
in addition it makes logical sense the lighter an object the easier it is to accelerate its velocity form 0 to some quantity 
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Highway transportation officials are trying to determine if the average speed on Archer road is above 45mph, the post speed limi
USPshnik [31]

Answer:

Option D) -0.0707

Explanation:

We are given the following in the question:  

Population mean, μ = 45 mp

Sample mean, \bar{x} = 44.9

Sample size, n = 50

Sample standard deviation, s = 10

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{44.9 - 45}{\frac{10}{\sqrt{50}} } = -0.0707

Thus, the test statistic is

Option D) -0.0707

4 0
3 years ago
Abishek is a runner. He runs the 100 m sprint
konstantin123 [22]

Answer:

1.67m/s

Explanation:

Total Distance to be travelled by a Runner=100m

Time Taken=10*6s

Speed=Distance/Time

=100/10*6=10/6=1.67m/s

3 0
3 years ago
Read 2 more answers
A window air conditioner that consumes 1.4 kW of electricity when running and has a coefficient of performance of 3 is placed in
Shtirlitz [24]

Answer:

1.4 kJ/s

Explanation:

See attached photo

7 0
3 years ago
Which element below has chemical properties similar to the chemical properties of fluorine.
SVETLANKA909090 [29]
For number one the answer is Iodine because it is in the same group as fluorine. For number two the answer is Germanium for the same reason. For number three the answer is Aluminum for the same reason.
4 0
3 years ago
Please help Need good grade
ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the  range

Using formula of range

R=\dfrac{v^2\sin(2\theta)}{g}...(I)

The range for the other angle is

R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

Here, distance and speed are same

On comparing both range

\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

\sin120=\sin2(\alpha-60)

120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

6 0
4 years ago
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