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kondor19780726 [428]

3 years ago

5

Write an equation to represent the following situation. Justin wants to earn 500 minutes on Khan Academy He currently has 120 mi

nutes. If he spends 60 minutes per day, how many days will it take for him to reach his goal?

1 answer:

Alisiya [41]3 years ago

5 0

Answer:

500=120+60

Variable would either be M or D For 60

Step-by-step explanation:

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Four students about to purchase concert tickets for $18.50 for each ticket discover that they may purchase a block of 5 tickets

soldier1979 [14.2K]

So, its 18.5 per person
<span><span>
80/5=16
18.5-16=2.5

They would each save 2.5 dollars each.</span></span>

7 0

3 years ago

Solve the equation of exponential decay. The population of a city is expected to be 440,000 in 2020. This is a decline of 12% fr

DIA [1.3K]

Answer:

about 340,000

Step-by-step explanation:

In 10 years, the population dropped to 0.88 of what it was in 2010. At the same rate, in 20 more years, it will drop to 0.88² of what it was in 2020:

2040 population = 440,000·0.88² ≈ 340,000

5 0

4 years ago

Read 2 more answers

Pleasehelp, im inda stuck

padilas [110]

Answer:

I think the answer is C, sorry if I'm wrong

4 0

2 years ago

Read 2 more answers

SOMEONE, PLEASE ANSWER THIS!

IrinaVladis [17]

Answer:

Step-by-step explanation:

Solution

Start with the product

The product is 7*x where x is a number but not specified.

Now add 6

Answer: 7x + 6

This cannot be simplified any more than what it is now.

8 0

2 years ago

Read 2 more answers

Determine the next step for solving the quadratic equation by completing the square.

Studentka2010 [4]

Answer:

The solutions are $x=\frac{1+\sqrt{7}}{2}$ and $x=\frac{1-\sqrt{7}}{2}$

Step-by-step explanation:

we have

$0=-2x^{2}+2x+3$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$-3=-2x^{2}+2x$

Factor the leading coefficient

$-3=-2(x^{2}-x)$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$-3-0.5=-2(x^{2}-x+0.5^{2})$

$-3.5=-2(x^{2}-x+0.5^{2})$

Rewrite as perfect squares

$-3.5=-2(x-0.5)^{2}$

$7/4=(x-0.5)^{2}$

square root both sides

$x-0.5=(+/-)\sqrt{\frac{7}{4}}$

$x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1+\sqrt{7}}{2}$

$x=\frac{1-\sqrt{7}}{2}$

4 0

3 years ago