Answer:
a) (-367231.63i , 367231.63i, 0) N/C
b) (0 , 0 , 367231.63i ) N/C
Explanation:
a)
Case x < -2.15

Case x > 2.15

Case -2.15 < x <+2.15

b)
Case x < -2.15

Case x > 2.15

Case -2.15 < x <+2.15

Explanation:
Given that,
Fencing to be done, P = 400 m
Area of the rectangular garden, 
Let l is the length and b is the breadth of the garden. The area of the rectangle is given by :

............(1)
The perimeter of the garden is given by :


...............(2)
On solving equation (1) and (2), we get the value of l and b are as follows :
l = 90 m and b = 110 m
or
b = 90 m and l = 110 m
So, the dimension of the garden is 90 m by 110 m. Hence, this is the required solution.
Answer:

Explanation:
We must use conservation of linear momentum before and after the collision, 
Before the collision we have:

where these are the masses are initial velocities of both players.
After the collision we have:

since they clong together, acting as one body.
This means we have:

Or:

Which for our values is:

Answer:
The weight on the neutron star is 99.69 ×
N.
Explanation:
Here,
weight on earth is 665 N. We can calculate the mass as :
= mg
or, 665= m × 9.810
∴ m =
= 67.68 kg
Now weight of this mass on the surface of neutron star:
= 
= 
= 99.69 ×
N
The required weight is 99.69 ×
N.