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3 years ago

1. What average force is exerted on a 25 g egg by a bed sheet if the egg hits the sheet at 4 m/s and takes

Physics

1 answer:

attashe74 [19]3 years ago

5 0

Answer:

F = -0.5 N

Explanation:

Given that,

Mass of an egg, m = 25 g = 0.025 kg

Initial speed, u = 4 m/s

Final speed, v = 0 (it stops)

Time, t = 0.2 s

We need to find the average force exerted on the egg. The force is given by :

F = ma

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.025\times (0-4)}{0.2}\\\\F=-0.5\ N$

So, the average force exerted on the egg is (-0.5 N).

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A 2-kg bowling ball sits on top of a building that is 40 meters tall.

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The bowling ball is at rest, so it only has gravitational potential energy.

Ug = mgy
Ug = (2)(9.8)(40) = 784 J

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3 years ago

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A 1.50x103-kilogram car is traveling east at 30 meters per second.

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Answer:

$39000\ \text{kg m/s}$

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3 years ago

A flat coil of wire has an area A, N turns, and a resistance R. It is situated in a magnetic field, such that the normal to the

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Answer:

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Problem 4: A uniform flat disk of radius R and mass 2M is pivoted at point P A point mass of 1/2 M is attached to the edge of th

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From the case we know that:

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The moment of inerta with respect to point P on the disk without the point mass is Ip = 3MR².
The total moment of inertia (of the disk with the point mass with respect to point P) is I total = 5MR².

Please refer to the image below.

We know from the case, that:

m = 2M

r = R

m2 = 1/2M

distance between the center of mass to point P = p = R

Distance of the point mass to point P = d = 2R

We know that the moment of inertia for an uniform flat disk is 1/2mr². Then the moment of inertia for the uniform flat disk is:

Icm = 1/2mr²

Icm = 1/2(2M)(R²)

Icm = MR² ... (i)

Next, we will find the moment of inertia of the disk with respect to point P. We know that point P is positioned at the arc of the disk. Hence:

Ip = Icm + mp²

Ip = MR² + (2M)R²

Ip = 3MR² ... (ii)

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I total = Ip + I mass

I total = 3MR² + (1/2M)(2R)²

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Learn more about Uniform Flat Disk here: brainly.com/question/14595971

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