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3 years ago

1. What average force is exerted on a 25 g egg by a bed sheet if the egg hits the sheet at 4 m/s and takes

Physics

1 answer:

attashe74 [19]3 years ago

5 0

Answer:

F = -0.5 N

Explanation:

Given that,

Mass of an egg, m = 25 g = 0.025 kg

Initial speed, u = 4 m/s

Final speed, v = 0 (it stops)

Time, t = 0.2 s

We need to find the average force exerted on the egg. The force is given by :

F = ma

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.025\times (0-4)}{0.2}\\\\F=-0.5\ N$

So, the average force exerted on the egg is (-0.5 N).

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Explanation:

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2 years ago

Where is the magnetic south pole compared to the geographical north pole?

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3 years ago

Match the technology that uses radio waves to the field in which it is used

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Answer:

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Explanation:

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2 years ago

A current of 5.0 a flows through an electrical device for 10 seconds. how many electrons flow through this device during this ti

melisa1 [442]

1 Amp = 1 Coulomb/sec
1 Coulomb/sec = 6.25*10^18 electrons/sec

Therefore,
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3 years ago

Suppose you are pushing a 3 kg box with a force of 25 N (directed parallel to the ground) over a distance of 15 m. Afterward, th

alex41 [277]

Answer: 321 J

Explanation:

Given

Mass of the box $m=3\ kg$

Force applied is $F=25\ N$

Displacement of the box is $s=15\ m$

Velocity acquired by the box is $v=6\ m/s$

acceleration associated with it is $a=\dfrac{F}{m}$

$\Rightarrow a=\dfrac{25}{3}\ m/s^2$

Work done by force is $W=F\cdot s$

$W=25\times 15\\W=375\ J$

change in kinetic energy is $\Delta K$

$\Rightarrow \Delta K=\dfrac{1}{2}m(v^2-0)\\\\\Rightarrow \Delta K=\dfrac{1}{2}\times 3\times 6^2\\\\\Rightarrow \Delta K=\dfrac{1}{2}\times 3\times 36\\\\\Rightarrow \Delta K=54\ J$

According to work-energy theorem, work done by all the forces is equal to the change in the kinetic energy

$\Rightarrow W+W_f=\Delta K\quad [W_f=\text{Work done by friction}]\\\\\Rightarrow 375+W_f=54\\\Rightarrow W_f=-321\ J$

Therefore, the magnitude of work done by friction is $321\ J$

3 0

3 years ago