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Daniel [21]
3 years ago
7

Please answer this I'm sorry for annoying you

Physics
1 answer:
GalinKa [24]3 years ago
4 0

The resultant force points between <u><em>up</em></u> and <u><em>right</em></u>.

So if we're going to resolve it into two separate forces, they have to provide some force <u><em>up</em></u> and some force to the <u><em>right</em></u>.

The only pair of forces among the choices that does that is <em>choice-A</em> .

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Answer:

4.3 * 10 N

Explanation:

To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.

torque  = distance from pivot *  perpendicular force

170 Nm= 0.4 m * F

F = 425 N = 4.3 * 10 N rounded off to two significant figures

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A 12 v automobile battery is connected to an electric starter motor. the current through the motor is 206
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Power = (voltage) x (current). The motor consumes (12)x(206)=2,472 watts. Some of it is dissipated as heat, but most of it is used to do useful work by turning the engine over to make it start.
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A swimmer does 3560 j of work in 55 s what is the swimmers power output?
ankoles [38]

Explanation:

<em>Here </em><em>it </em><em>is </em><em>given </em>

<em>Work </em><em>(</em><em>W) </em><em> </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em> </em><em>J</em>

<em>Time </em><em>(</em><em>t) </em><em> </em><em>=</em><em> </em><em>5</em><em>5</em><em> </em><em>sec</em>

<em>power </em><em>(</em><em>P) </em><em> </em><em>=</em><em> </em><em>?</em>

<em>We </em><em>know </em><em>we </em><em>have </em><em>the </em><em>formula </em>

<em>p  = \frac{w}{t}</em>

<em>P </em><em>=</em><em> </em><em>3</em><em>5</em><em>6</em><em>0</em><em>/</em><em>5</em><em>5</em>

<em>P </em><em>=</em><em> </em><em>6</em><em>4</em><em>.</em><em>7</em><em>3</em><em> </em><em>watt</em>

8 0
3 years ago
An electron has a velocity of 1.50 km/s (in the positive x direction) and an acceleration of 2.00 ✕ 1012 m/s2 (in the positive z
olga nikolaevna [1]

Answer:

see explanation

Explanation:

Given that,

velocity of 1.50 km/s = 1.50 × 10³m/s

acceleration of 2.00 ✕ 1012 m/s2

electric field has a magnitude of strength of 18.0 N/C

\bar F= q[\bar E + \bar V \times \bar B]\\\\\bar F = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]\\\\\\m \bar a = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]

9.1 \times 10^-^3^1 \times 2\times 10^1^2 \hat k=-1.6\times10^-^1^9 \hat k [18\hat k+ 1.5\times 10^3 \hat i \times (B_x \hat i +B_y \hat j +B_z \hat k)]42.2 \times 10^-^1^9 \hat k = -2.4 \times 10^1^6B_y \hat k + 2.4 \times 10 ^1^6 \hat j B_z\\

B_x = undetermined

B_y = \frac{42.2 \times 10^-^1^9}{-2.4 \times 10^-^1^6} \\\\= - 0.0176 T

B_z = 0T

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4 years ago
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Answer:what???

Explanation:

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