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Nat2105 [25]
3 years ago
9

The 25-lb slender rod has a length of 6 ft. using a collar of negligible mass, its end a is confined to move along the smooth ci

rcular bar of radius 3√2 ft. end b rests on the floor, for which the coefficient of kinetic friction is b = 0.4. if the bar is released from rest when  = 30, determine the angular acceleration of the bar at this instant.
Physics
1 answer:
sp2606 [1]3 years ago
3 0
Which of the following is NOT a factor in efficiency?<span><span>A.metabolism</span><span>B.type of movement</span><span>C.muscle efficiency</span><span>D.digestion</span></span>
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As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh
MrMuchimi

Answer:37^{\circ} North of west

Explanation:

Given

40,000-ton luxury line traveling 20 knots towards west and

60,000 ton freighter traveling towards North with 10 knots

suppose v is the common velocity after collision

conserving momentum in west direction

20\times 40,000=(20,000+60,000)v\cos \theta

suppose the final velocity makes \theta angle with x axis

v\cos \theta =10----1

Conserving Momentum in North direction

10\times 60,000=80,000\times v\sin\theta

v\sin \theta =\frac{15}{2}----2

divide 1 and 2

\tan \theta =\frac{3}{4}

\theta =37^{\circ}

so search in the area 37^{\circ} North of west to find the ship

3 0
3 years ago
HELP NOWWW Studies based on which of the following were used to describe the current model of the atom?
alexgriva [62]
Well I know that ernest rutherford did the gold foil experiment where he fired alpha particles at gold foil. This experiment founded the nucleus but I don't know if the current model of the atom is based on this.

Cathode ray tube experiments sounds like its to do with electrolysis so i dont think it can be that.

6 0
3 years ago
Read 2 more answers
Help! PROJECTILE PROBLEM: A 7500-kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25
dsp73
Here, 

height at failure, h1 = 525 m, 
upward acceleration, a = 2.25 m/s^2, 
velocity = v m/s, 
<span>
SO, </span>
<span>
v^2 = 2*a*h = 2*2.25*525 = 2362.5 </span>
Now, acceleration, g = 9.8 m/s^2, 
<span>
SO, </span>
<span>
heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters </span>
Hence, 
<span>
a) </span>
Total height = 525+120.54 = 645.54 meters 

b) 
<span>time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec 

---------------------------------

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
4 0
3 years ago
Read 2 more answers
A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a
iren [92.7K]

Answer:

√(6ax)

Explanation:

Hi!

The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:

x=(1/2)at^2

Then the we need to find the time t' for which the displacement is 3x

3x=(1/2)a(t')^2

Solving for t':

t'=√(6x/a)

Now, the velocity of the motorcycle as a function of time is:

v(t)=a*t

Evaluating at t=t'

v(t')=a*√(6x/a)=√(6*x*a)

Which is the final velocity

Have a nice day!

3 0
3 years ago
LVULAN
3241004551 [841]

For this case we have that by definition, the kinetic energy is given by the following formula:

k= \frac {1} {2} * m * v ^ 2

Where:

m: It is the mass

v: It is the velocity

According to the data we have to:

m = 100 \ kg\\v = 9 \frac {m} {s}

Substituting the values we have:

k = \frac {1} {2} * (100) * (9) ^ 2\\k = \frac {1} {2} * (100) * 81\\k = 50 * 81\\k = 4050

finally, the kinetic energy is 4050 \ J

Answer:

Option A

7 0
3 years ago
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