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Marysya12 [62]
3 years ago
14

In your own words, describe the purpose of using a chemical equation.

Physics
2 answers:
Scilla [17]3 years ago
7 0
Chemical equations show how chemicals interact when a reaction occurs. They use symbols and formulas to show the chemical reaction so that chemical names do not need to be written out. They also help keep track of all elements and the number of atoms of each element on each side of the equation.
Mars2501 [29]3 years ago
7 0

Answer:

The purpose of using a chemical reaction is to diagram a reaction, where the left side is formed by reactants and the right side is formed by the product. Through diagraming a reaction, chemists can hypothetically change parts of the both components, that way they would see what to expect in the reaction. Also, they can measure the approximation of amount of mass they would need, and see how components will change after the reaction

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In a game of pool, the cue ball moves at a speed of 2 m/s toward the eight ball. When the cue ball hits the eight ball, the cue
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a)  p₀ = 1.2 kg m / s

b) p_f = 1.2 kg m / s  

c)    v_{2f} = 1.278 m/s

d)1.2482 =v_{2f} cos θ

e)  0.2736 =v_{2f}sin θ

g) θ = 12.36

<h3>What is momentum?</h3>

Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.

According to the question,

We define a system formed by the two balls, which are isolated and the forces during the collision are internal.

Hence , the momentum is conserved

a) The momentum of the system before the collision:

p_o = m v_1_0 + 0         p_o= 0.6 2         p_o = 1.2 kg m / s

b) The momentum of the system after the collision, as the system is isolated, the momentum is conserved so

p_f = 1.2 kg m / s

d. On X axis

p_ox = 1.2 kg m / s

p_{fx}= m v1f cos 20 + m v2f cos θ

p_o = p_f

1.2 = 0.6 (-0.8) cos 20+ 0.6v_{2f} cos θ

1.2482 =v_{2f} cos θ

e. On Y axis  

p_{oy} = 0

p_{fy}= mv_{1f}sin 20 + mv_{2f}cos θ

0 = 0.6 (-0.8) sin 20 + 0.6 v_{2f} sin θ

0.2736 =v_{2f}sin θ

Here,

g. we write our system of equations

0.2736 =v_{2f} sin θ

1.2482 = v_{2f} cos θ

0.219 = tan θ (divide)

θ = tan⁻¹ 0.21919

θ = 12.36

c. Now To find the velocity

0.2736 = v_{2f} sin θ

v_{2f}= 0.2736 / sin 12.36

v_{2f} = 1.278 m / s

Learn more about momentum here:

brainly.com/question/4956182

#SPJ1

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