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Soloha48 [4]
3 years ago
7

Under the Big Top elephant. Ella [2500 kg]. is attracted to Phant, the 3,000 kg elephant. They are separated by 8 m. What is the

gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)​​
Physics
2 answers:
Dafna11 [192]3 years ago
8 0

Hi there!

We can use the same equation for Gravitational Force:

\large\boxed{F_g = G\frac{m_1m_2}{r^2}}

Fg = force due to gravity (N)

G = gravitational constant

m1,m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the values provided:

F_g = (6.67*10^{-11})\frac{(2500)(3000)}{8^2} = \large\boxed{7.814 * 10^{-6}N }

Andreas93 [3]3 years ago
7 0

\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}

Here we've been given,

  • Universal gravitational constant (G) = \sf{6.67 \times  {10}^{ - 11} }

  • Mass of object 1 (m1) = 2500 kg

  • Mass of object 2 (m2) = 3000 kg

  • Distance between two objects (r) = 8 m

We have to find the gravitational attraction force (Fg) = ?

The standard formula to solve is given by,

:\implies\tt{F_g = g \frac{m_1m_2}{ {r}^{2} } }

:\implies\tt{F_g = 6.67 \times  {10}^{ - 11}  \times  \frac{(2500 )(3000)}{ {8}^{2} } }

:\implies\tt{F_g = 6.67 \times  {10}^{ - 11} \times  \frac{7500000}{64}  }

:\implies\tt{F_g = 7.814 \times  {10}^{ - 6} }

  • Gravitational force of attraction is 7.814 × 10^-6 N.
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