Question

Under the Big Top elephant. Ella [2500 kg]. is attracted to Phant, the 3,000 kg elephant. They are separated by 8 m. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)​​

Answer 1

Hi there!

We can use the same equation for Gravitational Force:

$\large\boxed{F_g = G\frac{m_1m_2}{r^2}}$

Fg = force due to gravity (N)

G = gravitational constant

m1,m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the values provided:

$F_g = (6.67*10^{-11})\frac{(2500)(3000)}{8^2} = \large\boxed{7.814 * 10^{-6}N }$

Answer 2

$\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}$

Here we've been given,

• Universal gravitational constant (G) = $\sf{6.67 \times {10}^{ - 11} }$

• Mass of object 1 (m1) = 2500 kg

• Mass of object 2 (m2) = 3000 kg

• Distance between two objects (r) = 8 m

We have to find the gravitational attraction force (Fg) = ?

The standard formula to solve is given by,

$:\implies\tt{F_g = g \frac{m_1m_2}{ {r}^{2} } }$

$:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{(2500 )(3000)}{ {8}^{2} } }$

$:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{7500000}{64} }$

$:\implies\tt{F_g = 7.814 \times {10}^{ - 6} }$

• Gravitational force of attraction is 7.814 × 10^-6 N.