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4 years ago

A cheetah can run at a maximum speed

Physics

1 answer:

vivado [14]4 years ago

3 0

Answer:

25 seconds (rounded up to nearest one second)

Explanation:

Cheetah's speed = 91.8 km/h

Gazelle's speed = 77.9 km/h

Both animals are running at full speed with the gazelle 97.3 m ahead.

Converting their respective speeds to m/s ;

Cheetah's speed = $\frac{91.8 * 1000}{3600}$ = 25.5 m/s

Gazelle's speed = $\frac{77.9 * 1000}{3600}$ = 21.6 m/s (correct to one decimal place)

Assuming the gazelle stops, cheetah will run at 25.5 m/s - 21.6 m/s = 3.9 m/s to catch its prey (gazelle).

Time = distance ÷ speed

The time cheetah will take to catch its prey = 97.3 m ÷ 3.9 m/s = 24.94871795 s = 25 seconds (rounded up to nearest one second)

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A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at

faust18 [17]

The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

<h3>What is the resultant force the two engines exert on the rocket?</h3>

The resultant force on the rocket is calculated thus:

The 513N thrust is resolved into vertical and horizontal components;

Horizontal component: 513N cos(32.4°) = 433.14 N

Vertical component: 513N sin(32.4°) = 274.88 N

Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N

Total force at right angles:

0 + 274.88 N = 274.88 N

The resultant force (F) is then given as follows:

F² = a² + b²

F² = (1158.14 N)² + (274.88 N)²

F = √1,416,847.27

F = 1,190.3

To find the direction:

tan X 274.88 N / 1,158.14 N

X = tan⁻¹ 0.237346089419241

X = 13.35°

Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.

Learn more about resultant force at: brainly.com/question/17434363

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8 0

2 years ago

A force of 20N changes the position of a body. If mass of the body is 2kg, find the acceleration produced in the body.2. A ball

shepuryov [24]

Explanation:

Hello there!!!

You just need to use simple formula for force and momentum, 

F= m.a

and momentum (p)= m.v

where m= mass

v= velocity.

a= acceleration .

And the solutions are in pictures. 

Hope it helps..

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3 years ago

Ground-based radio telescopes can collect data from distant objects in space

Arada [10]

Answer is A. Because the telescope are use in night

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3 years ago

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Water has a high heat capacity. What does this term mean? a) Water is relatively resistant to an increase in temperature. b) Wat

Delicious77 [7]

Answer:a) Water is relatively resistant to an increase in temperature

Explanation:

Water has relatively high heat capacity i.e. it requires high amount of heat to raise a little increase in temperature.

Heat capacity is defined as ability of molecule to absorb heat . Mathematically heat capacity is defined as

$C=\frac{Q}{\Delta T}$

where $C=heat\ capacity$

$Q=heat\ interaction$

$\Delta T=change\ in\ Temperature$

4 0

4 years ago

g A hydraulic press has a safety feature which consists of a hydraulic cylinder with a piston at one end and a safety valve at t

nlexa [21]

Answer:

58.32 N

Explanation:

Area of a circle = $\pi$ $r^{2}$

where r is the radius of the circle.

The cylinder has a radius of 0.02 m, its area is;

$A_{1}$ = $\pi$ $r^{2}$

= $\frac{22}{7}$ x $(0.02)^{2}$

= $\frac{22}{7}$ x 0.0004

= 1.2571 x $10^{-3}$

Area of the cylinder is 0.0013 $m^{2}$ .

The safety valve has a radius of 0.0075 m, its area is;

$A_{2}$ = $\pi$ $r^{2}$

= $\frac{22}{7}$ x $(0.0075)^{2}$

= $\frac{22}{7}$ x 5.625 x $10^{-5}$

= 1.7679 x $10^{-4}$

Area of the valve is 0.00018 $m^{2}$ .

From Hooke's law, the force on the safety valve can be determined by;

F = ke

$F_{2}$ = 950 x 0.0085

= 8.075 N

Minimum force, $F_{1}$ , required can be determined by;

$\frac{F_{1} }{A_{1} }$ = $\frac{F_{2} }{A_{2} }$

$\frac{F_{1} }{0.0013}$ = $\frac{8.075}{0.00018}$

$F_{1}$ = $\frac{0.0013 *8.075}{0.00018}$

= 58.32

The minimum force that must be exerted on the piston is 58.32 N.

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3 years ago