Question

The density of water is 1.00 g/cm3. what is the density of the oil in the left column of the u-tube shown below is

Answer 1

Hello!

Your answer would be:

$P_{A}$ = $P_{B}$
⇒$P_{0}$ + $p_{0}$$^{h}$ = $P_{0}$ + $p_{w} h_{w}$ ; where $h_{w}$ = h - 2cm
⇒$P_{0}$ = $\frac{ P_{w} h_{w} }{h}$ = $\frac{1 * (0.1 - 0.02)}{0.1}$ = 0.8 g/$cm^{3}$ = 800 kg/$m^{3}$


I hoped this helped. c;