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sesenic [268]
3 years ago
8

What is work in science

Physics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

The scientific defenision of work reveals its relationship to energy; whenever work is done, energy is transfered.

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Dmitrij [34]
Take 10m/s^2 for the gravitational acceleration, as we know this is a free fall, we can use the equation: d=1/2*g*t^2

Substitute g=10m/s^2, t=5s, d=125m
7 0
3 years ago
Learning Goal: To practice Problem-Solving Strategy 30.1 Electromagnetic Induction. A coil of wire contains N turns and has an e
Helen [10]

Answer:

Time interval for which magnetic field reduced to ZERO is given as

t = \frac{NB_0\pi a^2}{RI}

Explanation:

As we know that the flux linked with one coil is given as

\phi = B_0 A

\phi = B_0(\pi a^2)

now total flux of all coils is given as

\phi = NB_0\pi a^2

now let say the flux is reduced to ZERO after time "t"

so as per Faraday's law EMF induced in the coil is given as

EMF = \frac{NB_0\pi a^2 - 0}{t}

now the current in the coil is given as

I = \frac{EMF}{R}

I = \frac{NB_0\pi a^2}{Rt}

so the time interval is given as

t = \frac{NB_0\pi a^2}{RI}

8 0
4 years ago
"On a movie set, an alien spacecraft is to be lifted to a height of 32.0 m for use in a scene. The 260.0-kg spacecraft is attach
Lisa [10]

Answer:

<em>The time interval required to lift the spacecraft to this specified height is 123.94 seconds</em>

Explanation:

Height through which the spacecraft is to be lifted = 32.0 m

Mass of the spacecraft = 260.0 kg

Four crew member each pull with a power of 135 W

18.0% of the mechanical energy is lost to friction.

work done in this situation is proportional to the mechanical energy used to move the spacecraft up

work done = (weight of spacecraft) x (the height through which it is lifted)

but the weight of spacecraft = mg

where m is the mass,

and g is acceleration due to gravity 9.81 m/s

weight of spacecraft = 260 x 9.81 = 2550.6 N

work done on the space craft = weight x height

==> work = 2550.6 x 32 = 81619.2 J

this is equal to the mechanical energy delivered to the system

18.0% of this mechanical energy delivered to the pulley is lost to friction.

this means that

0.18 x 81619.2  = <em>14691.456 J  </em> is lost to friction.

Total useful mechanical energy =  81619.2 J - 14691.456 J = 66927.74<em> J</em>

Total power delivered by the crew to do this work = 135 x 4 = 540 W

But we know tat power is the rate at which work is done i.e

P = \frac{w}{t}

where p is the power

where w is the useful work done

t is the time taken to do this work

imputing values, we'll have

540 = 66927.74/t

t = 66927.74/540

time taken t = <em>123.94 seconds</em>

8 0
3 years ago
Question 1:
german

Answer:

well I done really know ask the others person

7 0
3 years ago
**20points**
polet [3.4K]
B) a new element is formed
3 0
4 years ago
Read 2 more answers
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