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2 years ago

5

Explain how heat as a reactant or product in a chemical reaction makes the change endothermic or exothermic?

2 answers:

USPshnik [31]2 years ago

8 0

Answer:

Heat as a reactant makes the change endothermic, while heat as a product makes the change exothermic.

Explanation:

In an endothermic reaction, heat is a reactant, making the endothermic reaction cooler than its surroundings. This can be compared to how an ice cube melting requires heat as a reactant.

In an exothermic reaction, heat is a product, making the exothermic reaction hotter than its surroundings. This is compared to how a fire releases heat into the air as a product.

gregori [183]2 years ago

7 0

✅Chemical reactions often involve changes in energy due to the breaking and formation of bonds. Reactions in which energy is released are exothermic reactions, while those that take in heat energy are endothermic.

IamSugarBee

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a_sh-v [17]

Explanation:

⁶⁵₃₀Ca → ⁶⁵₂₉Sc + ⁿₓH

The reaction above is nuclear reaction.

In a nuclear reaction, the mass number and atomic number must be conserved.

The mass number is the superscript before the atom

Atomic number is the subscript before the atom

Conserving mass number:

65 = 65 + n

n = 0

conserving atomic number:

30 = 29 + x

x = 1

The unknown atom is a positron i.e a positively charged electron: ⁰₁e

⁶⁵₃₀Ca → ⁶⁵₂₉Sc + ⁰₁e

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2 years ago

calculate the mass of 120cc nitrogen present at STP. how many number of molecules are present in it?

Stells [14]

Answer:

$0.15008\ \text{g}$

$3.23\times 10^{21}$

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of $N_2$ = $\dfrac{120}{22400}=0.00536\ \text{mol}$

M = Molar mass of $N_2$ = $28\ \text{g/mol}$

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

Mass of $N_2$ is

$m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}$

Mass of the nitrogen is $0.15008\ \text{g}$

Number of molecules is given by

$nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}$

The number of molecules present in it are $3.23\times 10^{21}$

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2 years ago

How many moles are 21.67 L of NH4CI?<br> Type your answer...

NNADVOKAT [17]

Answer:

0.967mole

Explanation:

Given parameters:

Volume of NH₄Cl = 21.67L

Unknown:

Number of moles = ?

Solution:

We assume that the volume was taken at standard temperature and pressure,

Then;

Number of moles = $\frac{volume }{22.4L}$

Number of moles = $\frac{21.67}{22.4}$ = 0.967mole

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