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Leokris [45]
3 years ago
6

does a positive charge make the atomic radius smaller? and does a negative charge make the atomic radius bigger? yes or no.

Chemistry
1 answer:
Goryan [66]3 years ago
4 0
The answer to the question is no it doesn’t
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1) will water boil at 100 degrees celsius whether it has 20 mg or 200 mg of weight?
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Answer:

yes water boils at 100 degree Celsius but the boiling point water is different at different place because of the altitude of that place. For example boiling point of water is 96 decree Celsius.

No the 2 solutions don't boils at same time. it's because of their volume.

if the volume is more then it takes more time to boli. and vice versa

8 0
3 years ago
Which example does not involve knowledge of chemistry?
Trava [24]

I would honestly say C. All others have ingredients in them that makes them work, the combination of stuff to put out the fire, film is made from a certain material and drugs are an ovbious mixture. Looking at the stars is the only thing you don't need chemistry for.

6 0
3 years ago
Read 2 more answers
The atomic nucleus contains?
ycow [4]
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8 0
3 years ago
For each of the acid–base reactions, calculate the mass (in grams) of each acid necessary to completely react with and neutraliz
LiRa [457]

Acid-base neutralization reaction is defined as reaction of acid with base to form corresponding salt and water. Strong acid and base completely neutralize each other.

(a) The acid base neutralization reaction is as follows:

HCl(aq)+NaOH(aq)\rightarrow H_{2}O(l)+NaCl(g)

From the above balanced chemical reaction, 1 mol of NaOH completely reacts with 1 mol of HCl. The mass of NaOH is given 4.85 g, convert this into number of moles as follows:

n=\frac{m}{M}

Molar mass of NaOH is 39.997 g/mol, thus,

n=\frac{4.85 g}{39.997 g/mol}=0.121 mol

Thus, 0.121 mol of NaOH reacts with same amount of HCl and number of moles of HCl will be 0.121 mol.

Since. molar mass of HCl is 36.46 g/mol, thus, mass can be calculated as follows:

m=n\times M=0.121 mol\times 36.46 g/mol=4.421 g

Therefore, 4.421 g of HCl completely reacts with 4.85 g of NaCl.

(b) The acid base neutralization reaction is as follows:

2HNO_{3}(aq)+Ca(OH)_{2}(aq)\rightarrow 2H_{2}O(l)+Ca(NO_{3})_{2}(aq)

From the above balanced chemical reaction, 1 mol of Ca(OH)_{2} completely reacts with 2 mol of  HNO_{3}. The mass of Ca(OH)_{2}   is given 4.85 g, convert this into number of moles as follows:

n=\frac{m}{M}

Molar mass of Ca(OH)_{2}  is 74.093 g/mol, thus,

n=\frac{4.85 g}{74.093 g/mol}=0.06545 mol

Thus, 0.06545 mol of Ca(OH)_{2} reacts with 2\times 0.06545 mol=0.13091 mol of HNO_{3}

Since. molar mass of HNO_{3} is 63.01 g/mol, thus, mass can be calculated as follows:

m=n\times M=0.13091 mol\times 63.01 g/mol=8.25 g

Therefore, 8.25 g of HNO_{3} completely reacts with 4.85 g of Ca(OH)_{2}.

(c) The acid base neutralization reaction is as follows:

H_{2}SO_{4}(aq)+2 KOH (aq)\rightarrow 2H_{2}O(l)+K_{2}SO_{4}(aq)

From the above balanced chemical reaction, 2 mol of KOH completely reacts with 1 mol of  H_{2}SO_{4}. The mass of KOH  is given 4.85 g, convert this into number of moles as follows:

n=\frac{m}{M}

Molar mass of KOH  is 56.1056 g/mol, thus,

n=\frac{4.85 g}{56.1056 g/mol}=0.0864 mol

Thus, 0.0864 mol of KOH reacts with \frac{0.0864 mol}{2}=0.0432 mol of H_{2}SO_{4}

Since. molar mass of H_{2}SO_{4} is 98.079 g/mol, thus, mass can be calculated as follows:

m=n\times M=0.0432 mol\times 98.079 g/mol=4.24 g

Therefore, 4.24 g of KOH completely reacts with 4.85 g of H_{2}SO_{4}.

8 0
3 years ago
Which of the five type of equilibrium problems best applies to this question: Consider the following reaction at equilibrium. Wh
andreev551 [17]

Answer:

d

Explanation:

3 0
3 years ago
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