All categories

3 years ago

What is the empirical formula for P4O10?

Chemistry

2 answers:

Sphinxa [80]3 years ago

8 0

Answer: P2O5

Explanation: You divide both subscripts by 2 to get the empirical formula.

bija089 [108]3 years ago

3 0

Answer:

Formula of P4O10 is P2O5.

Explanation:

WE GET IT BY DIVIDING BOTH SUBSCRIPTS BY 2.

You might be interested in

A solution contains naphthalene (c10h8) dissolved in hexane (c6h14) at a concentration of 10.00 % naphthalene by mass. part a ca

IceJOKER [234]

Answer : The vapor pressure of hexane = 140.5055 torr

Solution : Given,

Concentration of Naphthalene by mass = 10 %

Vapor pressure of pure Hexane = 151 torr

From the periodic table, the molar masses of Naphthalene and Hexane are:

Molar mass of Naphthalene = 128 g/mole

Molar mass of Hexane = 86 g/mole

From the Raoult's law, the vapor pressure of the component is equal to the vapor pressure of the pure component multiplied by its mole fraction.

Formula used :

$P_{i}=P_{i}^{*}\times x_{i}$ ..............(1)

Where,

$P_{i}$ = vapor pressure of component i

$P_{i}^{*}$ = vapor pressure of pure component i

$x_{i}$ = mole fraction of of component i in the solution

For this problem, few steps are involved:

step 1 : concentration of 10% naphthalene by mass means 10 g of naphthalene present in 100 g of solution.

This means,

The mass of naphthalene = 10 g

The mass of hexane = 100 - 10 = 90 g

step 2 : find the number of moles of naphthalene and hexane.

Formula used :

Number of moles = $\frac{\text{ Given mass}}{\text{ Molar mass}}$

Moles of Naphthalene = $\frac{10g}{128g/mole}$ = 0.0781 moles

Moles of Hexane = $\frac{90g}{86g/mole}$ = 1.0465 moles

Total moles = Moles of Naphthalene + Moles of Hexane

= 0.0781 + 1.0465 = 1.1246 moles

step 3 : Now, calculate mole fraction of Hexane

Mole fraction of Hexane = $\frac{\text{ Moles of Hexane}}{\text{ Total moles}}$ = $\frac{1.0465}{1.1246}$ = 0.9305

step 4 : Now, find the vapor pressure of Hexane by using above formula (1).

$P_{i}=P_{i}^{*}\times x_{i}$

Now put all the values in this formula, we get

Vapor pressure of Hexane = Vapor pressure of pure Hexane × Mole fraction of Hexane

$P_{i}$ = 151 torr × 0.9305 = 140.5055 torr

7 0

3 years ago

Read 2 more answers

Enter your answer in the provided box. Oxidation of gaseous ClF by F2 yields liquid ClF3, an important fluorinating agent. Use t

MakcuM [25]

Answer : The value of $\Delta H_{rxn}$ for the reaction is, -135.2 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of $ClF_3$ will be,

$ClF(g)+F_2(g)\rightarrow ClF_3(l)$ $\Delta H_{rxn}=?$

The intermediate balanced chemical reaction will be,

(1) $2ClF(g)+O_2(g)\rightarrow Cl_2O(g)+OF_2(g)$ $\Delta H_1=167.5kJ$

(2) $2F_2(g)+O_2(g)\rightarrow 2OF_2(g)$ $\Delta H_2=-43.5kJ$

(3) $2ClF_3(l)+2O_2(g)\rightarrow Cl_2O(g)+3OF_2(g)$ $\Delta H_3=394.4kJ$

We are dividing the reaction 1, 2 and 3 and reversing reaction 3 and then adding all the equations, we get :

(1) $ClF(g)+\frac{1}{2}O_2(g)\rightarrow \frac{1}{2}Cl_2O(g)+\frac{1}{2}OF_2(g)$ $\Delta H_1=\frac{167.5kJ}{2}=83.75kJ$

(2) $F_2(g)+\frac{1}{2}O_2(g)\rightarrow OF_2(g)$ $\Delta H_2=\frac{-43.5kJ}{2}=-21.75kJ$

(3) $\frac{1}{2}Cl_2O(g)+\frac{3}{2}OF_2(g)\rightarrow ClF_3(l)+O_2(g)$ $\Delta H_3=\frac{-394.4kJ}{2}=-197.2kJ$

The expression for enthalpy of formation of $ClF_3$ will be,

$\Delta H_{rxn}=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H_{rxn}=(83.75kJ)+(-21.75kJ)+(-197.2kJ)$

$\Delta H_{rxn}=-135.2kJ$

Therefore, the value of $\Delta H_{rxn}$ for the reaction is, -135.2 kJ

5 0

4 years ago

Consider the substitution reaction that rakes place when (R)-3-bromo 3-methylhexane is treated with methanol. Which of the follo

Otrada [13]

Answer:

The reaction would take place with racemization.

Explanation:

The compound (R)-3-bromo 3-methylhexane contains has the leaving group attached to a tertiary carbon atom. When the leaving group is attached to a tertiary carbon atom, the compound undergoes nucleophilic substitution via SN1 mechanism. This mechanism involves the formation of a planar carbocation intermediate. The nucleophile may attack this intermediate from either faces, leading to racemization of the product.

5 0

3 years ago

Compare table salt and glucose

Luba_88 [7]

The salt is soluble to the water but the glucose aka sugar is not.

7 0

3 years ago

Sort these six events from the earliest to the most recent. 1. Democritus proposes the existence of atoms 3rd 2. Dalton's atomic

Nitella [24]

Explanation:

1. Democritus proposes the existence of atoms

2. Dalton's atomic theory

3. J. J. Thomson discovers the electron

4. Rutherford's gold foil experiment

5. Bohr model

6. Schrödinger's Wave Mechanics model of the atom

The first idea about matter containing atoms dates back to Greek philosophers. One of them was Democritus .

In 1808 Dalton put forward his atomic theory

In 1897 J.J Thomson discovered cathode rays using his gas discharge tube experiment.

In 1911, Ernest Rutherford proposed the nuclear model of the atom using experiments on the gold foil.

Neils Bohr in 1913 suggested his own atomic model

Erwin Schrodinger formulated the wave equation of electrons

Learn more;

Dalton atomic theory brainly.com/question/1979129

Rutherford gold foil experiment brainly.com/question/1859083

#learnwithBrainly

4 0

3 years ago