White dwarfs<span> are formed from the collapse of low mass </span>stars<span>, less than about 10 time the mass of the Sun. This </span>star<span> loses most of its mass in a wind, leaving behind a core that is less than 1.44 solar mass. On the other hand,</span>neutron stars<span> are formed in the catastrophic collapse of the core of a massive </span>star.
Answer:
955.5N
Explanation:
The normal force is given by the difference between the centripetal force and gravity at the top of the loop:
![F_N = F_C - F_G = m\frac{v^{2} }{r} - mg](https://tex.z-dn.net/?f=F_N%20%3D%20F_C%20-%20F_G%20%3D%20m%5Cfrac%7Bv%5E%7B2%7D%20%7D%7Br%7D%20-%20mg)
mass m = 65kg
radius of the loop r = 4m
velocity v = ?
g = 9.8 m/s²
To find the centripetal force, you need to find the velocity of the car at the top of the loop.
Use energy conservation:
![E_{tot}=mgh + \frac{1}{2} mv^{2}](https://tex.z-dn.net/?f=E_%7Btot%7D%3Dmgh%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D)
At the top of the hill:
![E_{tot}= mgh_{hill}](https://tex.z-dn.net/?f=E_%7Btot%7D%3D%20mgh_%7Bhill%7D)
At the top of the loop:
![E_{tot}=mgh_{loo}_p +\frac{1}{2} m v^{2}](https://tex.z-dn.net/?f=E_%7Btot%7D%3Dmgh_%7Bloo%7D_p%20%2B%5Cfrac%7B1%7D%7B2%7D%20m%20v%5E%7B2%7D)
Setting both energies equal and canceling the mass m gives:
![gh_{hill} = gh_{loo}_p + \frac{1}{2} v^{2}](https://tex.z-dn.net/?f=gh_%7Bhill%7D%20%3D%20gh_%7Bloo%7D_p%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20v%5E%7B2%7D)
Solving for v:
![v^{2} = 2g(h_{hill}-h_{loo}_p)](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%202g%28h_%7Bhill%7D-h_%7Bloo%7D_p%29)
Using v in the first equation:
![F_N = 955.5N](https://tex.z-dn.net/?f=F_N%20%3D%20955.5N)
K = C + 273, so 27°C = 27+273 = 300 K
1 dg = 100 mg, so 20 dg = 20×100 = 2,000 mg
That's the 'electrostatic' force.
Answer:
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