Answer: 3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
Answer:
Moles = 0.271 mol
Solution:
Step 1: Calculate Mass of Br₂ as;
Density = Mass ÷ Volume
Solving for Mass,
Mass = Density × Volume
Putting values,
Mass = 3.12 g.mL⁻¹ × 13.9 mL
Mass = 43.36 g
Step 2: Calculate Moles of Br₂ as;
Moles = Mass ÷ M.Mass
Putting values,
Moles = 43.36 g ÷ 159.80 g.mol⁻¹
Moles = 0.271 mol
The molecular formula of sucrose is - C₁₂H₂₂O₁₁
molecular mass of sucrose - 342 g/mol
molarity of sucrose solution is 0.758 M
In 1 L solution the number of sucrose moles are - 0.758 mol
Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L
= 1.17 mol
The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g
