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maria [59]
2 years ago
12

How can these objects all weigh the same but be different sizes?

Chemistry
1 answer:
Mrrafil [7]2 years ago
5 0
Density/Earth’s gravitational pull.
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A chemistry student needs 50.0 g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, t
slamgirl [31]

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density = \frac{mass}{volume}

It is given that mass is 50 g and density is 0.934 g/cm^{3}.

Hence, calculate the volume of methyl acetate as follows.

                     Density = \frac{mass}{volume}

             0.934 g/cm^{3} = \frac{50 g}{volume}

                       Volume = 53.53 cm^{3}

or,                                  = 53.53 ml                (as 1 cm^{3} = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is 53.53 ml.

3 0
2 years ago
The formation of iodine is described by the following chemical equation:
olga nikolaevna [1]

Answer:

N2O2(g) +O2(g) ===> 2NO2(g)

Explanation:

For a nonelementary reaction, the reaction equation is described as the sum of all the steps involved. All these steps constitute the reaction mechanism. Each step in the mechanism is an elementary reaction. The rate law of the overall reaction involves the rate determining step (slowest step) in the reaction sequence.

Now look at the overall reaction 2NO(g) + O2(g) ---------> 2NO2(g)

The two steps in the mechanism are

2NO(g) --------->N2O2(g) (fast)

N2O2(g) +O2(g) -------> 2NO2(g) (slow)

Summing all the steps and cancelling out the intermediate N2O2(g), we obtain the reaction equation;

2NO(g) + O2(g) ---------> 2NO2(g)

Hence the answer.

7 0
2 years ago
What percentage of the mass of hydrofluoric acid (HF) is contributed by hydrogen?
Morgarella [4.7K]

This problem is asking for the percent by mass of hydrogen in hydrofluoric acid. At the end, the answer turns out to be D. 5%​ as shown below:

<h3>Percent compositions:</h3>

In chemistry, percent compositions are used for us to know the relative amount of a specific element in a compound. In order to do so for hydrogen, we use the following formula, which can also be applied to any other element in a given compound:

\% H=\frac{m_H*1}{M_{HF}}*100\%

Where m_H stands for the atomic mass of hydrogen and M_{HF} for the molar mass of hydrofluoric acid. In such a way, we plug in the atomic masses of hydrogen (1.01 g/mol) and fluorine (19.0 g/mol) to obtain:

\% H=\frac{1.01g/mol*1}{1.01g/mol+19.0g/mol}*100\%\\\\\% H=5\%

Learn more about percent compositions: brainly.com/question/12247957

5 0
2 years ago
What tool did scientist use to first study the Earth’s interior
IgorC [24]
Seismic waves hope this helps.
5 0
2 years ago
What is the primary role of the United States Bureau of Counterterrorism?
zubka84 [21]

o advance counterterrorism efforts in other countries

7 0
3 years ago
Read 2 more answers
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