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Alex777 [14]
3 years ago
11

Question 3 Unsaved

Physics
2 answers:
natka813 [3]3 years ago
7 0

Sub-surface mining involves digging tunnels and shafts to deep underground.

Answer: Option 4

<u>Explanation: </u>

Mining is the process of extracting ores of minerals from the earth crust depending upon the presence of ores in the earth crust position. Some mineral ores are tend to present in the surface of earth crust.

In order to extract them, surface mining is done. Strip mining and open pit mining are types of surface mining. This type of mining does not require tunnelling and digging deep shafts as the ores can be obtained from the upper layers of earth crust.

Smelting is the process of extracting minerals from the ores, so it is not a process of mining. Thus, sub-surface mining uses digging tunnels and shafts as they are required to extract ores buried in the deep underground of earth crust.

faltersainse [42]3 years ago
5 0
Subsurface mining is the answer it's late though lol
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A.
Brut [27]

Answer:

\boxed{\sf Work \ done = 4 \ J}

Given:

Force = 8 N

Distance covered by the body = 50 cm = 0.5 m

Explanation:

Work Done = Force × Distance covered by the body

= 8 × 0.5

= 4 J

6 0
3 years ago
1. The large wheels on the train have a mass of 0.5 kg, while the small wheels have a mass of 0.15 kg. The train body, and child
blsea [12.9K]

Answer: 60.975 Joules

KE = 1/2 mv^2

=> 1/2 * 40.65 * 3

=> 60.975 J

5 0
3 years ago
What happens to a current when the electric field in the wire increase
Gnom [1K]

Answer:

If the voltage is increased then the electric field is higher, and electron velocity (average) is proportional to this field. Then you have an increase in speed. And current is total charge passing per time unit, so current is proportional to velocity value of charge (and to voltage in resistors and wire).

Explanation:

5 0
4 years ago
H. A truck starts to move from rest. If it gains the acceleration of 3 m/s2 in 5 sec,
SashulF [63]

Answer:

1. The final velocity of the truck is 15 m/s

2. The distance travelled by the truck is 37.5 m

Explanation:

1. Determination of the final velocity

Initial velocity (u) = 0 m/s

Acceleration (a) = 3 m/s²

Time (t) = 5 s

Final velocity (v) =?

The final velocity of the truck can be obtained as follow:

v = u + at

v = 0 + (3 × 5)

v = 0 + 15

v = 15 m/s

Therefore, the final velocity of the truck is 15 m/s

2. Determination of the distance travelled

Initial velocity (u) = 0 m/s

Acceleration (a) = 3 m/s²

Time (t) = 5 s

Distance (s) =?

The distance travelled by the truck can be obtained as follow:

s = ut + ½at²

s = (0 × 5) + (½ × 3 × 5²)

s = 0 + (½ × 3 × 25)

s = 0 + 37.5

s = 37.5 m

Therefore, the distance travelled by the truck is 37.5 m

6 0
3 years ago
a large truck has a mass of 20000kg. it is traveling at 28m/s along a staright road . calculate the kinetic energy ​
Semmy [17]

Answer:

The answer is

<h2>7,840,000 J</h2>

Explanation:

The kinetic energy KE of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}  \\

where

m is the mass

v is the velocity

From the question

m = 20000kg

v = 28 m/s

It's kinetic energy is

KE =  \frac{1}{2}  \times 20000 \times  {28}^{2}  \\  = 10000 \times 784

We have the final answer as

<h3>7,840,000 J</h3>

Hope this helps you

3 0
4 years ago
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